but this does not utilize T = F.D "Torque = Force x Distance.
OK, let me have an attempt at it.
I will need your help/correction to establish some facts.
Shaft I is the input and is turning CW
Torque of shaft I is divided
Ti = Ts2 + Tc1 (1)
Since C2 is not turning "leave...
Can T = F . d by used?
what I am after at this stage is how to use the above in order to arrive to the answer which I see that you maybe able to obtain it via other ways as indicated previously using efficiency and power.
If 1 foot-pound is applied at I and using T=Fd, what are the steps in...
zekeman:
I want to calculate the torque using T = F.d
and to simplify things we will write c1 to mean the radius of left train carrier, s2 to mean the radius of the right train sun p2 to mean the radius of the right train planetary and so on.
zekeman:
You assumed a common ring gear is hard for me to see.
the representation shows the right train ring gear is part of the left train sun gear but has a different radius i.e number of teeth.
I think I got it all wrong.
I tried to deduce the concept from
http://www.roymech.co.uk/Useful_Tables/Drive/Epi_cyclic_gears.html
I will need help understanding it step by step in the link above Example 1.
why P = -NA /NP in the second raw?
I understand that - means opposite direction of...
I think I made a mistake.
it should be
1 + (Nd/Nx).(Nb/Nd).(Ne/Nc).(Na/Ne)
and not
1 + (Nd/Nx).(Nb/Nd).(Ne/Nb).(Na/Ne)
so if we let
Nx = Nc = Nd = Ne = 30
Nb = Na = 90
then
Na = 1 + (1 . 3 . 1 . 3) = 10
i.e. speed increase from 1 to 10 turns.
Now I will go and find out how to figure the torque...
Could some one second this please...
Revolution in the output shaft S will be
1 + (Nd/Nx).(Nb/Nd).(Ne/Nb).(Na/Ne)
But I think I am missing the Ny part of it. can some one help please?
thx
what I am after is the equation to solve this. BTW it is not a homework/exam request.
I was reading some examples on http://www.roymech.co.uk/Useful_Tables/Drive/Epi_cyclic_gears.html
but I could not work my problem out.
thx
Hi
Please view the image file below.
I am at lose on how to find the number of revolution and the torque of the S shaft when the L shaft is turned 1 revolution at 1 foot-pound.
If possible, please give a step by step with explanation.
Thanks a million.