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  1. abedneirat

    Contribution from Utility Distribution Load for 3-phase and 1-phase-Ground faults

    Hi Musa The contribution from distribution will be mainly by Motors . it equals 4 x Nominal Current . also you should consider the asymmetric factor for total load . I sc_asym = K * I sc_sym ; K = 1 to 2 ; practically it can be considered = 1.7 max ; Fault Current = K * Isc_sym + 4 *...

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