Oh I give up on the symbols. It previews fine, but then they don't show, I'm pasting them from another thread, is there a toolbar I can download for those or something?
-Todd
Well the symbols for BH (?) value and flux (?) didn't read in my post before in the calcultions so let me try and paste it again
***********************************************************
reluctance S = g/(?0*A)
where g is the airgap length (m), A is the airgap cross-sectional area (m²),
?0...
...by UKpete below. I would prefer to avoid calculus as I only had one year and that knowledge is rapidly rusting away (no line integrals please)
*********************************************************
reluctance S = g/(?0*A)
where g is the airgap length (m), A is the airgap cross-sectional...
...by UKpete below. I would prefer to avoid calculus as I only had one year and that knowledge is rapidly rusting away (no line integrals please)
*********************************************************
reluctance S = g/(?0*A)
where g is the airgap length (m), A is the airgap cross-sectional...
Thanks for the tip on the acrylic, I had no idea! It just might work for my application. Normally a materials dielectric strength / thickness goes down with greater thickness due to more impurities and flaws in a thicker part, but you seem to say it's the other way around here(?)
Also, can you...
I may have found the material to use, it's called Pyrolytic Boron Nitride (PBN)and it is supposed to have the highest dielectric strength known: 200,000v/mm
I would still be interested to hear input on other materials as I would assume that the PBN is probably pricey and doesn't seem like it's...
I am searching for insulator materials with the highest dielectric strength per thickness possible. The best ones I've found seem to be Teflon @ about 40-80 kV / mm (short time) and CPVC @ about 40 kV / mm (short time).
My problem is that all the values I find say "short time", but this is not...
Well I don't mean to stray from the original topic of this thread, but I thought that iron had higher saturation than any carbon steel. Isn't that why pure iron is often used for the pole pieces? I guess I need to find some good charts with the curves shown for these materials, but I'd still be...
Hi everyone,
Newbie question here; MJR2 said in one response that there would be more losses using pure iron than 1020 steel, why is that?
thanks
-Todd
Thanks for confirming MJR2's model (MJR2, how could I ever have doubted you?) I was still working on a PM design, but I really think I will hve to abandon it now. Maybe the electromagnet will really be easier to deal with, and possibly cheaper anyway, safer to construct I'm sure. My little...
You may be interested to check out www.fusor.net for amature fusion(primarily) and fission discussion. The site is more or less dedicated to the "fusor" a simple electrostatic device that seems to inefficiently produce a fusion reaction (pretty solid evidence it's not an "O.P." or "stripping...
Thanks a lot for that electromagnet design, it gives me a really good idea of what kind of an electromagnet it would take and I could pretty much use that design exactly, except for changing the poles to round.
I think that by using an electromagnet it might be possible to design it so that the...
This magnetic circuit is for what is basically a cyclotron, and is just for my own experiments / hobbyist satisfaction. I have a goal of attaining certain energies of particles so I am definitely trying hard to maximize the field across the gap.
Basically increasing the B field by using tapering...
Thanks once again to UKPete, and yes the cobalt material is almost as expensive as the magnets themselves!
Well MJR2, thanks for modeling this design, but I must say that that figure is dissapointing to me. I was sure I could get at least 20,000G. by concentrating the flux from an area of 15cm...
I actually meant Bg=13500/(1+(1/10))=12272.72G Not Br=....
Am I still incorrect?
It's my understanding that one uses the total magnet length in series when figuring for the flux density at the gap i.e. 5cm + 5cm=10, but your figue tends to agree more closely with what I get from the online...
...cm^2
then use a pole piece to reduce to a 10cm dia surface of:
78.54 cm^2
with a perfect pole piece material I would have
(176.71/78.54)*(12272.72G)=27612.83G
Any estimates on what kind of percentage loss I could expect using annealed soft iron pole pieces?
Thanks again
-Todd Massure
I'm working on a design for a magnetic dipole with a steel yoke, most likely using permanent neodymium magnets. My goal is to achieve the highest field possible across a gap over a certain minimum area, with an emphasis on uniformity of the field over this area.
My question is if I use a cone...
I'm having trouble finding a formula for energy loss of a single particle after one revolution in a cyclotron due to cyclotron radiation.
Can anyone help?
Thanks
-Todd
