Dear Guys,
I'm looking for the ASME SA-928. Could it be, that the ASTM A928 is not transferred into the ASME SA-928 standard?
I have only the 2008 version of the ASME IIA at the moment but there is no ASME SA-928.
Could someone tell me if its included in the latest version or not?
Thanks a lot!
Simple Answer:
Hold:
1.) Notification yes
2.) hold activity until inspector can witness or you have official waiver
witness
1.) Notification yes
2.) proceed regardless if inspector is present or not
monitoring
1.) Notification no
2.) just proceed like a witness. Monitoring means the inspector...
Are you sure. I don't think that a quick heating up to 1040°C and rapid quenching can change the ferrite/austenit ratio due to holding times of some minutes.
Nevertheless is there a Para or clarification which helbs me to proof this interpretation?
Hello metengr,
tzhanks for your quick response.
Your view seems logical but where can I find a proof for this interpretastion. The ASME is not very clear.
Dear all,
I have a question regarding ASME IX (2010) QW 407.4.
"QW-407.4 For ferrous base metals other than P-No. 7,
P-No. 8, and P-No. 45, when a procedure qualification test
coupon receives a postweId heat treatment exceeding the
upper transformation temperature or a solution heat treatment...
I agree with arunmrao. The exposure time will be shorter because of the higher energy. But you loose sensitivity.
Multiple films is normaly used when you want to cover big difference in the wall thicknes. e.g. you have a part with 10 mm wall thickness next to 20 mm wall thickness. The you can...
Yes we do it like redpicker said.
For temperatures about -20°C we use a ethanol bath in a normal refrigiator (but takes quit long to cool it down.).
for temperatures up to -50°C we use dry ice (carbon dioxide) in combination with the ethanol bath (works quiet quick) and for temperatur up to...
Hi,
there are different methods.
You can use a point count (or computer based analysis) (see thread723-288690 ) which is imo the best way and you can determinate in exact areas like weld metal, heat affected area and base metal).
Next option is using a Ferritoscope (by Fischer) to determinate...
Hey Guys I have a question about the acceptance limits according API 5LC.
For example for round indications there is a table with columnes
size Adjacent size Minimum Separation Maximum Number in any 6 in/152,4 mm
first row is
size: 3,2 mm adjacent size: 3,2 mm Minimum Separation 50,8 mm...
I think it depends what you do or want do do with your material. But I read a lot of specs where it's required.
But degaussing means not to take away the ability to react to a permanent magnet (which is probably your test if the material is magnetic or not)its only that the material do not act...
Hi!
2205 and S31803 is only slightly different.
According to my experience both materials should be lightly magnetic.
The best way to find out what kind of material you have is to to an PMI with an XRF or OAES. an XRF type leaxes also no burn marks like the OAES but is not that accurate.
Its an...
Thanks for the quick response guys.
Yes I was checking the ASTM A 999 but its still not very clear. If it would be a "kind of leak test" where you survey the pressure lost you could pressurize the pipe alwayys with the same pressure (for example 10 bar). But you need to calculate the test...
Hi Everyone,
I have a question. Is there anywhere a clear definitaion what a hydrostatic pressure test is? I mean the pressure test of a single pipe (by the manufacturer) not a complete system.
Is the test a leak test, where you pressurize to the test pressure, stop pumping and see if the pipe...
Practice B:
This practice describes the procedure for conducting the
boiling 120-h ferric sulfate–50 % sulfuric acid test.
As result you measure the weight loss and calculate a corrosion rate (millimetre per month).
Practice E:
This practice describes the procedure by which the
copper–copper...
Hi and welcome here,
2nd party is a inspection by personell independent from the production (usally the QC/QA of the company).
So you have to pay them anyway and it gets cheaper;)
3rd party is somone totally independent from the manufacturer/company. (like Lloyds Register, TÜV, and so on).
...(1,15(D-2t)/(e-D/t-2e-1))-t
D is for example 16" or 406,4 mm
t = 0,204" or 5,2 mm
e = 0,1025" or 102,5 mm
I think that the formula is not correct coz i found in an old version (1991) A = (1,15(D-2t)/(e*D/t-2e-1))-t
But when I try to calculate i don't get realistic results.
What am i doing...