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oops ! There was a typo in the original post. T2 is directed back toward the lift beam which would be up and to the right. dvd - sorry i didn't notice the typo previously, not i understand why you wrote the equation that way. dersertfox - thanks, that deeper insight into the 2nd equation...

dvd, Lug 2 is to the left and above Lug 1 and T2 is directed up and to the right...the vertical component and the horizontal component of T2 both produce a cw moment about Lug 1. The CG is to the left of Lug 1 and W is directed down which produces a ccw moment about Lug 1...therefore the...

unclesyd, nice website...but not much help in my question. anyone? thanks, jdkuhndog

what website?

...up to the left at an angle from the horziontal of 15 degrees. W = 100# at the CG. This is what I did: Sum Forces in Y direction EQ1: T1+T2*sin(15) = 100# Sum Moments about Lug 1 EQ2: T2*sin(15)*51"+T2*cos(15)*50" = (100#)*(1") Solve Equations: T2 = 1.6#, T1=99.6# So, I was trying to...

Thanks for the info NickE & metengr.

I know this is a pretty stupid question...but i couldn't find a definition on the internet or in any of my books...what exactly is meant by 'Hot-Wrought'? I want to use a material A576 Grade 1045 Hot Rolled for an 8" diameter round I need for a wheel. But in the selection guide i am using, it...

Thanks for the links guys...they proved useful. I will be posing this following question to some vendors...but, didn't know if anybody had some insight into it... What is the corrosive resistance difference between ASTM A564 Type 630 Condition H1150 versus ASTM A276 Grade 316 Condition A ...

Is A276 Type 316 Condition B a stainless steel that is produced/used much? I have called this out in a calculation and then come to find that our local stainless distributor does not stock it and has never heard of it being requested. Does anybody stock it? I was trying to avoid the more...

Here is a link to a summary of some testing done with CO2 blasting...is this what you are referring to? http://sti.srs.gov/fulltext/tr2003084/tr2003084.pdf page 11 has a good picture of the CO2 pellets.

nornrich, I believe the relationship is outside corner radius = 2xwall thickness. jdkuhndog

...remembered a calc. that I had done a year or so ago that required torque capacity of a clutch... From Mark's Handbook 9th edition, page 8-39 T=0.5*i*f*F*D i = number of pairs of contact surfaces = 1 f = coefficient of friction = 0.03 F = axial Force applied = 6100# D = mean diameter =...

Thanks for the comments... I have made a phone call to a company which manufactures these lower blocks with a rotating hook. The chief engineer there told me that they really don't have a calc that they perform to ensure that the wires won't twist...they have had it only happen to them once...

The gearmotor for rotating the hook is located on the lower block. Let me try to be a little more clear on what is going on. I have a lower block with 4 sheaves - 8 parts of wire rope...right now I am considering the wire rope to have no effect on resisting the twisting effect. The lower...

...required Torque for the gearmotor on the lower block for rotating the load: T1 = Torsion due to load inertia T2 = Torsion due to friction = 149 lb*in WK^2 = mass moment of inertia of load = 3063 lb*ft^2 t = time to accelerate = 5 seconds R = ratio between hook and gearmotor = 6.7 N = RPM of...

Tagger, where/how is this shaft supported?

No. The stresses imposed on components must meet a Standard... for bending ultimate/5 for transv. shear stress ultimate/(5 * sqrt(3)) for torsional ultimate/(5* sqrt(3))...for combined bending and torsional by Von Mises..allowable = ultimate/5. so, I am aware what I need to check...was just...

Thanks liberty. Yes, I usually do combine stresses. The reason I am asking about the bending in this case, is that I have seen calculations that don't even consider bending in this case. They assume that the clevis is a pure shear connection.

...= 0.44 in^2 Sx = 0.041 in^3 Shear Stress = 1/2 x (5.5) / 0.44 = 6.25 ksi but if I would analyze the bending here it would be... M = PL/4 = 5.5*1.34/4 = 1.84 in*kips (if analyzed as simply supported) M = PL/8 = 5.5*1.34/8 = 0.92 in*kips (if analyzed as fixed) Bending Stress = M/S =...

The solenoid is sized for 40 pound force. With the lever advantage it has over the spring, there is really no concern for this. We have a special design that requires the hoist to be raised prior to the solenoid acting to release the brake...this will take friction between the pawl and ratchet...