I send a sample file now.
Regards
Note: there is a free "professional" software better than rho32: search for ipi2win.
https://files.engineering.com/getfile.aspx?folder=e018e41f-5cea-4930-a5ac-6a9801237a0c&file=rho32.dat
Saiedsadat,
I am not sure if the Standards have such probability coefficients.
More transformers, more fault current, but current to ground are no increased, because the bigger fraction of current returns via neutral to the transformers.
In some cases the neutrals of transformers can be...
Saiedsadat,
In low voltage circuit, the current to ground can't be bigger than Uphase/Rground, or Uline/sqrt(3)/Rground.
I assumed that your Uphase was 0.217 kV as the figure you sent, really is is 0.400/sqrt(3)= 231 V.
Rground is the resistance to ground of your grid1 electrode.
The SC...
Saiedsadat,
The 75 kA may be correct as fault to metallic circuit, but the current injected to ground cannot be bigger than 0.217/Rground, surely a small fraction of 75 kA.
Regards,
...--------
With this, the time for first point is zero
The second point time is 0.477225214242935*349= 166.5515998 us
It is not a integer submultiple of the period = 1/60 = 16666.6666666 us
The third point time is 0.477225214242935*698= 333.1031995 us
It is not a integer submultiple of...
Bacon4life,
I am developing Gtpplot as an EMTP-ATP viewer. The program can read COMTRADE files, but I have not access to true COMTRADE files, I am retired since 1996.
Any example of such file are welcome, I can correct the reader using it as a reference.
The signal has harmonics that are not...
Tofulover,
A bit better.
The problem with the standard is that the tables are coarse, any deviation from the exact R(V) or I(t) multiply the errors.
If you try with RF > 0 (using the graphic method) the errors are bigger.
It is a case where one must have faith... and I have not faith in the...
Tofulover,
You calculated the third column of your table (Ibody) applying the BF factor
1000/775= 1290 mA but you have 1719 mA (1290/0.75)
Are you using the third column to calculate Utp?
If yes, you calculate Utp using 1/0.75 times de current.
Regards,
OPH. 2020-06-22 09:53
Tofulover,
You obtained a table of I(V) and R(I) with exact values for the table values, and a good approximation for the rest of values.
Now, you can use a table of I(t) (or t(I)) to calculate V(t), as the EN50522, with the HF, BF and Weight for each case.
The last step is to compare your...
Tofulover
The paper shows how to solve the non-linear circuit graphically.
The tables are from a old Standard, I obtained the coefficients for R(V) 50% with the table if EN50522:
There are a lot of linear (as Excel use in your figure) and non-linear fitters.
Vtouch Table EN50522...
...was done linearly, from x=1 to 10 in 0.1 steps, but the second figure was calculated with
the procedure x--> log10(x)--interpolate--with a log-log table, and recover the interpolated value by y=10**y
The interpolation is linear in both cases, surely it is simple in Excel.
Regards,
...yo will see curves with reverse form as required, as arcs of rope.
Interpolating with log(x) and log(y) and reversing the values by 10**(log(y)), the shape of the curves are better respected. Using a preserving shape interpolation, the result are the best.
I am not user of Excel, but...
All the Standards define Current as the variable that can produce risk, and finally all define tables or curves of Voltage.
Look the Current(time) for different Standards (or author in one case), some obsolete.
Depending of how the Standard define Rbody the calculation will be easy (IEEE 80...
...A of EN50522
Vt - Zt(HtoH)- Zt (HtoF)- Ib
25V - 3250 ohm - 2438 ohm - 11mA
50V - 2500 ohm - 1875 ohm - 27mA
In your sample, Rcorrected= 3250*BF = 3250*0.75= 2438 (you did this part)
For rigth hand to both foot: HF=0.80
Icorrected=11/0.80= 13.75 mA
If you need only this circuit, it is OK...
...Rbody = 1000 Ohm. It is a easy work.
But for EN50522, Vtouch=GPR-Potential, but Ibody requires to solve the non-linear circuit Vtouch=Ibody*RF+Ibody*Rbody(Vbody), for all the area of interest.
Erdep programs solve this circuit for any of the four cases of EN50522, but one at the time.
It...
Tofulover,
The link to the Fortran code:
https://www.dropbox.com/s/1h57g7hitc8eiwj/touchall.f?dl=0
It can be compiled with Mingw32, Gfortran or Intel compilers.
Regards,
OPH. 2020-06-19 16:28
Tofulover
No, it is not a simple job to do it manually.
The simplest method is the bisection:
Link
But in this case you have not a closed function to calculate.
You have one (or more) tables with few values.
You must found a value in a table, and the best is to use interpolation.
But...
