ahmedradi
Electrical
- Feb 2, 2009
- 5
Hi everyone,
I'm confused about how to model a 3-winding transformer as three 2-winding transformers in star-formation. I was under the impression that it is a simple Delta-to-Star conversion of the impedances, but it is not according to some.
I've got an Autotransformer with a delta tertiary winding 330/132/22kV, 490MVA with the following impedances based on its rate:
Zps = 0.2081 pu
Zpt = 1.0045 pu
Zst = 0.7530 pu
If I follow a conventional Delta-to-Star transformation, then:
Zp=(Zps*Zpt)/(Zps+Zpt+Zst) = 0.10635 pu
Zs=(Zps*Zst)/(Zps+Zpt+Zst) = 0.01967 pu
Zt=(Zpt*Zst)/(Zps+Zpt+Zst) = 0.38481 pu
However, according to a different formula it should be:
Zp = (Zps + Zpt -Zst) / 2 = 0.2298 pu
Zs = (Zps + Zst -Zpt) / 2 = -0.0217 pu
Zt = (Zpt + Zst -Zps) / 2 = 0.7747 pu
Which of these calculations is right and on what bases?!
Thanks in advance for your help.
-Radi
I'm confused about how to model a 3-winding transformer as three 2-winding transformers in star-formation. I was under the impression that it is a simple Delta-to-Star conversion of the impedances, but it is not according to some.
I've got an Autotransformer with a delta tertiary winding 330/132/22kV, 490MVA with the following impedances based on its rate:
Zps = 0.2081 pu
Zpt = 1.0045 pu
Zst = 0.7530 pu
If I follow a conventional Delta-to-Star transformation, then:
Zp=(Zps*Zpt)/(Zps+Zpt+Zst) = 0.10635 pu
Zs=(Zps*Zst)/(Zps+Zpt+Zst) = 0.01967 pu
Zt=(Zpt*Zst)/(Zps+Zpt+Zst) = 0.38481 pu
However, according to a different formula it should be:
Zp = (Zps + Zpt -Zst) / 2 = 0.2298 pu
Zs = (Zps + Zst -Zpt) / 2 = -0.0217 pu
Zt = (Zpt + Zst -Zps) / 2 = 0.7747 pu
Which of these calculations is right and on what bases?!
Thanks in advance for your help.
-Radi