Hello. It has been a while. Thanks for your patience and previous help.
A quick recap: In Jerry and my industry we evaluate multi end spool quality by catenary. Placing the spool on a shaft with tensioning capabilities, and clamping the ends of a band of wire to ensure that they start at...
Your right, i had some random error in my calculation, the sag would be more like 1.1 inches. 0.284 lb/in^3 *.015 *.015 *Pi/4 = 5.018*10^-5. (5.018*10-5 *960^2)/(8/5.25lb) = 1.10"
i will continue later, i am on vacation the rest of the week.
sorry i took so long, i was running lab tests.
In essence the 7 ends are fused together, then pulled the 960" and placed under a 5.25 lb. load. The ends are coming of a metering unit that is intended to payoff equal amounts of wire. Since it can not truly be exact in length, i believe...
Here is the first set of circumstances that JerryV and i are attempting to solve.
A band of 7 clamped cables are pulled 960" from a locked multi-cable "precision" metered source which can be assumed fixed. The clamped group (to negate cable to cable shifting) is placed under...
