Kerem,
I don't understand your comment, UMC3481 is a on the shelf standard IC, what do you mean by changing the IC ?
Do you mean change the brand because of difficulty in sourcing the supplier ?
Do you have other alternative suggest ?
I am looking for Transformerless AC/DC Converter IC. Anybody can help me on any semiconductors manufacturer do produce the IC of below rating :-
Input AC :- 220~240 V
Output DC :- 12 V
Output Current : 0.5A-1.0A
I have not resolve the issues, it is still hot using 10 ohms. If I use 50 ohms, the current is not enough to drive the motors. BTW, 50 ohms also get too hot. I wonder may be this IC is not suitable for continuous drive. Anyone experience any driver IC for continuous drive for 10 hours a day ...
1 sec for forward and 1 sec for reverse continuouly. If the speed is fast, it could be 0.8 sec each. I don't think it is a steady current as the speed is so fast. When I measured with DVM, the current I can see is range from 0.2 A to 0.6 A.
What I means is the motor oscillating in forward and reverse direction, and I measured the current thru a DVM connecting is serial with the resistor.
With my VR set to min (ie, 0.55 V at pin 4), Measured voltage of CD1 and CD2, is around 3 V. CD1 and CD2 are oscillating when motor forward and...
Pin CD1 and CD2 are tied to ground with capacitors of ceramic 0.1 uF. Measured voltage is range between 0-3-8 V when motor oscillation.
The current thru' the resistor I measured is 0.55-0.6 Amp at Max setting at the VR (5 Pin) to pin 4 of the BA6219B.
Yes. The resistor is overheat.
Another surprise is the spec said that the BA6219B power dissipation max is P=2200 mW and that means 130mA constant current into IC (at 18V).
And with the resistor is 10 ohm must be there, the current is 18 V over 20 ohms (10 ohm resistor plus 10 ohm motor resistance), the current always 0.9 A...
OK, let me tell all the information :-
The spec of the motor said that Norminal Voltage of the Motor is 12 V. RPM (freeload) is 5800, current 0.05 A. With Load, Speed is 5000 rpm, current 0.2 A.
The Pin 4 is connected to a Variable Resistor of 10 K. It is use to control the speed of the...
The motor resistance is 12 ohm when I measured. So total amp is 18V/22 ohm = 0.8 Amp. For the resistor wattage calculation, P= 0.8 x 0.8 x 10 = 10 watt. That means I need a 20 watt resistor. This is crazy, because 20 watt resistor will be damn big.
Is this means that the ROHM driver is...
jbartos,
7812 is supplying 12 V to the rest of the circuit.
radarray,
I don't understand why the datasheet ask to ensure that the 10 ohm must be there to prevent a short circuit, the datasheet never mention the wattage require for the resistor. I have try to eliminate the 10 ohm by connecting...
I am using BA6219 reversible motor driver from ROHM. The Resistor connected to the BA6129 is 10 ohm 5 Watt.
The 10 ohm is connected to input of the 18 V unregulated adaptor which is supply to Pin 8 of the motor driver. The 7812 output is supplying 12 V to the rest of the circuit.
7812 is not...
I am using BA6219 reversible motor driver from ROHM. The Resistor connected to the BA6219 is 10 ohm 5 Watt.
The 10 ohm is connected to input of the 18 V unregulated adaptor which is supply to Pin 8 of the motor driver. The 7812 output is supplying 12 V to the rest of the circuit.
7812 is not...
I have solve the problem, one of the AND gate IC in the circuit is damage. The circuit get very hot, might be due to the IC suck lots of current from the 7812. I replace the AND gate IC and the 7812 getting normal already.
