Recent content by waross

It's nice to be supported by "The Big Guys".

What happens in a crash if the mechanical release inadvertently opens the door or releases the latch? My GM pickups have had this covered. If the door handle is inadvertently operated during a crash, the doors don't unlatch. If you need to make an emergency exit, pull and release and pull again...

In the BMW the key does not operate a lock mechanism. The key activates a switch, so with a dead battery..........

Not safe assumptions. Is the EPR not considering the instance when all or most of the fault current does return through the earth? And remember that as well as increasing impedance with distance, the line conductor and the earth return conductor form a voltage divider and the voltage driving...

BMW. Battery dead, can't open the doors. YouTube video; just open the hood and back-feed power from the under-hood light. Ya, just open the door and pull the hood release, and then you can back-feed to open the doors. The SUV was in pretty bad shape. The doors were still locked when it went to...

Alternating current sets up circulating currents in conductors. Skin effect also comes into play. The higher the frequency the greater the losses for a given current in a given conductor. As an illustration of the effect at 60 Hz, I was at one time responsible for a 600 KVA, 277/480 Volt diesel...

The next time, rent a generator.

BUT; If you can do a no load start on wye, you should be able to do a no load start and run on wye/delta.

Without a load test, any correlation may be meaningless. But, on a wye connection at 230 Volts, each winding will see 133 Volts. By Ohm's law you may expect 28 Amps at 230 Volts delta. Or not. Why not a wye/delta start?

A "Do or Die" attitude taken to the ultimate conclusion.

You want the relay to pick up om a ground fault. The 300 Amp current represents a bolted fault, the worst case. In the real world a bolted fault is unlikely. Actual fault current will normally be less than the worst case bolted fault. Consider the case of a feeder shorting to an equipment...

Your wye is on the 15kV system. The line to neutral voltage will be 8660 Volts. That is the maximum voltage that the resistor will see during a line to ground fault. 8660 Volts / 29 Ohms = 299 Amps Then we have a wrong understanding of some misapplied information. The 299 Amps (Close enough to...

I think that you may be seeing RF induction heating from the switching frequency. I defer to jraef or Marke for comments about a filter.

Common practice in large industrial plants is to step down to 489V, 600V or 690V. That is the greatest portion of the load. Small local transformers are used to supply 120/240av and other lighting voltages. Often each lighting panel will be fed from an individual transformer mounted close to the...