Recent content by turbinef14

thanks for takeing the time to respond to my question it is nice to know there are people that are prepared to put themselves out and give their knowlege thanks turbine f14

thanks for your response i have dug into my physics books and found the this formula power= kg lifted xlifting speed in m/s divided by 9.81x efficency . is this the corect formula to use if i was not going through a gearbox and direct off a motor shaft . and is ans in watts or kilowatts i want...

how do i calculate the motor required to lift a mass eg mass = 75kg what hp is required

thanks lads for your replies you have restored my faith in human nature

thanks skogsgurra for your reply and the help you give to this forum

would someone please explain the term freewheeling diodes

thanks jammyjim there is a seperate motor to drive the brushes on top.it also has a air pressure swith mounted inside the cover

thanks for your help. the motor does have two sets of brushes on the commutator and is used to drive a m/c one of the brushes was not makeing contact on the slip ring would the motor still run once started and what problem would this have caused. again thak you for your help

could some one please tell me why a 415 v three phase motor has slip rings at one end of shaft and comutator at the other.