There are steel dowels in those 1/8" holes. If the torque of 240 in-lbs is applied to the center of plate, rigid plate, the force acting on each dowel pin is 240Lbf? Is it as easy as that, or am I missing something? Friction negligible.
easy there big guy. I couldn't post a photo from my phone so I just sent the url to a photo that would best represent it. it just happened to be on a student site.
If I have a rigid plate with a 240 inch-lb torque applied to it and I have two 1/8" holes each one spaced 1/2" (on centers) away from toque point on opposite sides of the torque, how much would my resistance force have to be at each hole (in inch-lbs) to resist the torque? Thanks!
