Ed,
The picture is of a mill similar to mine. The design and operation of the drive system is the same. You are correct. High production is not a primary concern. I would however like to make the system as reliable as possible. My mill is designed to produce ~8-10k board feet per day. On a good...
Ed,
Is there some reference material that you can suggest I read on the design of hydrostatic systems? I know that reading a book won't make me a hydraulics engineer however it may at least give me an understanding of those type of systems.
Ed,
I agree. I want to keep costs at a minimum. I also don't want to start replacing parts after a few hours or after the system doesn't work at all. In the past I've found that it's better to think (or dream) of something at least twice as long as I ever plan on using it before I spend the...
You are correct. I haven't settled on that motor yet. I just looked at a few to see what was available based on the torque requirements so far. Sorry for the scare.
I'm still at a loss as to the method of calculating the additional torque required while the saw is in the cut. I tried every...
I came up with 660 lbft to drive the carriage to 325 fpm in 1 second. This type of calculation is new to me so I didn't feel all that confident in my product.
The saw is configured as you envision. A log is loaded on the carriage and dogged or clamped in place. The carriage is then pulled...
desertfox,
You covered my question in your last post. The disadvantage I was speaking of was the radius of the drum, i.e., you multiplied the straight line pull by the drum radius.
During normal sawing operations, it is rare that I would ever drive the carriage up to full operating speed...
desertfox,
Are you saying that the 200 lb-ft need to be applied to the winch drum shaft, meaning your calculations take into account the mechanical disadvantage of the drum radius?
Another note, how much torque would be required to accelerate the carriage to speed in the 60" clearance?
Ed...
desertfox,
The cable wraps the drum 7 times forming a single layer. There is no change in diameter as the cable feeds on/off the drum. I did not calculate the inertia of the drum. Good point.
Thanks for the reply Ted. The 5000 lbs is total mass. Actually its a bit over the maximum mass. I added 20% to the weight of the carriage and the heaviest log that my mill will handle as a safety factor. The distance from the leading edge of the longest log that my mill will handle to the...
I read my posts and realized that I still haven't asked a clear question. I am trying to calculate the amount of torque that needs to be applied to the input shaft of the 13" diameter winch drum in order to move the carriage. One thing that I can't (or don't know how to) calculate is the amount...
Sorry, I left a few things out. The input shaft of the winch drum needs to turn ~95 rpm to pull the carriage at the required 325 fpm. The carriage is pulled along the track which moves the log or cant through the head saw. The hydraulic drive motor is then reversed to pull the carriage back to...
I am in the process of designing a hydraulic drive for a circular saw mill. I have most of the numbers worked out except one. I can't seem to calculate the torque required to move the carriage. The specs are as follows:
I need to move a 5000 lb (maximum total mass)carriage along a flat plane at...
