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Recent content by slader99

  1. slader99

    Pressure drop in pipe sections

    Thanks for the responses. As David mentioned it was the volume^1.87 that was throwing me for a loop. As Rconner suggested the 7.57 coefficent likely includes the cg term and would allow for my unit balance.
  2. slader99

    Pressure drop in pipe sections

    When calculating pressure drop in long pipes I've used the following formula. dp = 7.57*(q^1.85)*(L)*(10^4)) / ((d^5)*p) (1) where dp = pressure drop (kg/cm2) q = air volume flow at atmospheric conditions (FAD) (m3/min) L = length of pipe (m) d = inside diameter of pipe (mm)...

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