Tek-Tips is the largest IT community on the Internet today!

Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!

Register Log in
  • Congratulations cowski on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

Recent content by sjk

  1. sjk

    calculating inductive load.

    I just purchased a 1200 watt inverter.It's suppose to handle up to a 3000 watt surge.I plugged a 10 amp circular saw into it.It started up but my voltage dropped down to 30 some volts and took approx.7 seconds for the saw to reach full speed.Why does it take so long?Does the saw drawl more than...
  2. sjk

    900 HP motors

    rhatcher, I do know that these pump sizes were used in other customers plants with no problems. I realize that the motor voltage needs to be used to determine power but our customer will not open or pig tail the enclosure to find out the true volts. The equation I used to calculate motor power...
  3. sjk

    900 HP Motors

    For power I used the following formula: P = (1.73 x Amps x Volts x P.F. x Eff.)/746 P.F. being the motor Power Factor Eff. being the motor Efficiency Amps being the single leg current and Volts being the motor voltage of 2300 Stan K.
  4. sjk

    900 HP Motors

    I have two different size pumps using the same 900 HP, 2300VAC, 3PH, 60HZ motors. The pump efficiencies were determined using amp readings on the motors, with negligible losses between the motor and pump. Both pumps are determined to be 20% less effiecient than our curves show. We have these...
  5. sjk

    900 HP motors

    I have two different size pumps using the same 900 HP motors. The pump efficiency is being determined from the amp readings on the motors. Assuming very small losses in the gear box and Mech. seal I have 2 different size pumps that are both 20% less effiecient than our curves show. We also...
See more

Part and Inventory Search

Back
Top