Thanks for the reply Scott. So, it is that simple? You just take the voltage rating as indicated by the C class and multiply it by the ratio of the tap to the full primary current (assuming the secondary winding is equally distributed)?
Hoping someone can show me the proper method of how to calculate the following. Not sure how to calculate these and would like some guidance as to how it is done, not the actual voltage itself....
a) What voltage can a multi-ratio 600:5 C400 class CT drive while maintaining accuracy within 10%...
