If I want to know how an aluminum structure will respond to loads, I use the properties of aluminum. If I want to know how the rock in the field will respond, it would only make sense to use the properties of the rock in the field.
If using a paint pen, you could have different marks. If you typically use bar in 1/8" increments, you could write roman numerals with the number of eighths on each (1/8" = I, 1/4" = II, ... 5/8" = V, etc)
UPDATE:
Alex's method did what I was looking for, but it is bugged. I used Alex's method to create detail views of parts on the assembly drawing. However, everytime I opened the drawing all the views of the virtual parts were missing (dashed lines making a box with an "X" in it were the view...
My fourth edition of Hibbler has chapter 12 titled "Deflections of Beams and Shafts" and 4 of the 9 sub-sections starts with the three words "Statically Indeterminate Beams." Assuming this wasn't removed between the 4th and 6th editions, I don't know how much more attention you could ask for in...
The contractors were aware of the specs prior to testing (I would hope!). Maybe "the contractors, with years of experience" should know what it takes to meet the specs.
Standards exist for a reason. In this case, it is not your job to pick them, only to test them and report the results. If they...
I follow the assumption that extended warranties and insurance premiums are designed to make the companies offering them money. Don't get me wrong, I see the benefit. I would much rather pay slightly above the average cost of medical expenses for every month of my life than be socked with a bill...
Just got my copy of the Nov. 18 issue, which included the following editorial on "How to run a 'nonhollowed-out' company"
http://machinedesign.com/node/87044
If I'm understanding you correctly, I believe you just need to hit Alt+Enter.
This is the same as for creating multiple lines of text in the same cell in Excel as well.
-- MechEng2005
I remember the introductory physics course from MIT has videos available online that you can watch and there was a demonstration for each lecture.
The one I remember best is when the instructor stood with his back against the wall and a bowling ball on a pendelum. Hold the ball to your nose and...
First thing I notice is that in your example you have:
a*x1 + b*x1
This is the same as (a+b)*x1, so without more information the best you can do is find (a+b), but not an exact value for a or b.
For example, say a+b = 10. Your function will be the same for:
a=1, b=9
a=10, b=0
a=5.23, b=4.77...
