Hi all,
Could someone enlighten me on how fuel regulation in generators is achieved? I am aware that this is one of the functions of the governor module but some detail on how it is achieved will be helpful.
Pointers to relevant literature on the web will also be apprecialted.
Thanks everyone.
I finally found a way to represent my curves as fourier series equations (by setting up composite tables in Excel) rather than polynomials and have a much better approximation. The area under each curve was also obtained using approximate integration methods.
Thanks a lot for...
HI all,
Is it possible to have higher order polynomial trendlines (i.e. higher than 6) in Microsoft Excel? If not, are there any free apps I can use for the purpose.
Thanks.
Hello all,
Is it possible to find the area under a curve (or trendline, more importantly) in Microsoft Excel?
I have some curves in Excel and have fitted trendlines to these curves based on sixth order polynomials. I need to know if there is an add-in or function that will save me the trouble of...
Hello all,
I need information on the fuel consumption per hour for CAT diesel sets with the following ratings: 320kVA, 500kVA, 590kVA, 725kVA, 800kVA and 1000kVA. Any other information on their operating characteristics will be appreciated.
Thanks.
I'm working on a project (in microsoft excel) to develop electrical load profiles for non-metered consumers to help with the load management and peak shaving decision making.
So far, I have developed daily profiles based on available data and grouped the profiles by weekdays and weekends for...
I'm working on a project to develop electrical load profiles for non-metered consumers to help with the load management and peak shaving decision making.
So far, I have developed daily profiles based on available data and grouped the profiles by weekdays and weekends for each month.
The problem...
No problem, gerdsen.
First you'll agree that squareroot of 3 is about 1.732.
So, for a 500kVA, 3ph genny delivering 415 line voltage, the current capacity is (500 x 1000) / (415 x 1.732) = 695A.
The 1000 is to convert from kilovolts to volts.
Once again, its VA / (V x sqrt (3)).
Hope this helps.
For a three phase generator, the kVA is Current times Voltage times Sqrt(3), which makes the current that can be delivered equal to the Power divided by the product of Sqrt(3) and the voltage.
For a 500kVA, 3phase generator, the line voltage should be about 415V, which should give a deliverable...