You're right. I apologize. I do thank everyone for trying to help, it's just the concept of displacement and angular movement was the push I needed to see how I was viewing the problem wrong.
I'm done thinking about this for a long time, my mind needs to rest.
To Handleman: Your post is the epitome of unhelpful. Thank you for your condescending attitude.
To Dvd and Fex32: I want to thank both of you from the bottom of my heart. This problem has been eating at me for about a week. I used the work equation and finally achieved the result that everyone...
Yes, I agree with everything except the "1.414 times the actual axial force" that you stated with no proof.
Isn't this Statics 101?
When you have any object (in this case a pin) acting on a surface (the ramp/slot/slide wall), you have 2 components that can be drawn. One component is parallel...
This might help clear things up for me.
Please look at this attachment and tell me which point has the highest torque and why. Both points are experiencing the same Force vector.http://files.engineering.com/getfile.aspx?folder=6e5b5801-9647-43b9-927c-9285f4e23039&file=Torque_Query.xlsx
Finally, some math. Ok, maybe I have a gross misunderstanding of statics (my background is actually in Chemical Engineering).
I understand the h/sin@. That's what I've been using.
Why are you dividing F/sin@. Shouldn't it be F*sin@? If @ = 0 degrees (linear force directed straight to the...
To Zekeman and Trueblood: The mechanisms you are describing have a variable torque that increase at the midpoint (at 90 degrees, when the arm is r). Correct? Constant force and the arm gets larger, maxing at the midpoint. The torque curves described in literature have high start and end torques...
This cannot be correct. Look at any company that sells scotch-yoke actuators... any literature on them. They all say the same thing.
Scotch Yoke actuators have high breakaway and closing torque, with low running torque. That means the torque is NOT constant.
Just type it into google.
http://www.eng-tips.com/viewthread.cfm?qid=143012&page=130#post
The second to last post of this thread is exactly the question I am asking about. Who is right? Unfortunately, no one explains it and the link is dead.
Ok, yes, I understand that the perpendicular distance from the piston arm to the center of the crank is constant. And also, linear force is constant.
The point of my original question is why am I getting a constant torque in my calculations when it is accepted world-wide that scotch-yoke has...
The "arm" or what I called "effective radius" is not constant. It changes throughout the rotation of the circle.
The linear force applied is constant, but the angle of application changes throughout the rotation of the circle. This should mean that tangential force changes as well.
I'm...
Hi, I'm at the end of my rope on this problem. As I deal with different actuators, I thought it would be important to theoretically/mathematically predict the torque curves for them.
The principle of the scotch-yoke actuator is that two pistons move linearly and cause the shaft to rotate. Each...
