Recent content by DougMace

Makes sense! At least it makes sense now after reading more papers than I cared for. Thanks!

@JustSomeNerd: No worries! :) We've all been there. And under more "normal" cases, with significantly longer lengths of cable, your answer is correct.

Looks like the answer is in calculating bending stiffness, which is not trivial, and may involve FEA: https://journals.sagepub.com/doi/pdf/10.1177/1687814017711079 https://en.calameo.com/read/000622927b2c6530ddf20 Intuitively though, it makes sense that a thin wire with more tension has the same...

The tensions are INVERSELY proportional with the area for the same displacement at load.

But that's exactly the confusing part. If you look at these tools, they indicate lower tension for heavier cables at the same displacement. For example, for the same displacement, you get 1400N for a 2.5mm cable, 1200N for a 3mm cable and 700N for a 4mm cable. I think this needs to be...

And yet, something doesn't make sense. The tension somehow must also be dependent on the characteristics of the cable (area, material, etc). For the same displacement at the applied force, the tension will be different for different types of cables...

Thanks! I think so... I think I'm overthinking it. Another way to look at it is to take moments about a support point. Therefore tension * cable_displacement = applied_force * cable_length/2, which is the same as you suggested. And then, the force is given by a spring, which is proportional...

I'm looking for formulas that describe how a tensiometer (something like this: https://www.abqindustrial.net/store/tensitron-acx-25-1-digital-aircraft-cable-tension-meter-0-5-25-lbs-cable-selection-1-16-inch-3-32-inch-p-563-op-999_12441.html) works, so looking at a deflection in a section of a...