The one half of the circumference had me confused. I guess if you would sum the forces over the entire circumference, then they would cancel out? Is that the correct thinking?
I know that this has been explained in previous posts, but I still have some confusion. In designing a circular RC tank, using the PCA document, you get the shear/foot at the base of the wall from Tbl. A-12. You then transfer this shear to the slab via dowels. You then must account for this...
