In continuous domain the transfer function coefficients are OK. The problem is the value of the term 2^(1/2)/(2*pi*fcutoff) is almoust 0. And you are right, because an oscillator has that transfer function. The implemented transfer function (low-pass or high-pass filter) is making it's job just...
I want to thank you the fast replay.
First I'll ansver the second question. All my thinking was made in rad/sec. The reason is simple. When I'm implementing the Butterworth filter I have to write less at the denominator. If I had been using frequnecy the denominator expresion would have been: [1...
I'm quite new in Matlab\Simulink so I'm just learning how to use it.
The problem I had find: if I implement a low pass filter (Butterworth aproximation) using the Simulink's transfer function (numerator: [1], denomerator: [1 2^(1/2) 1]), a foreign frequency component apears in the spectrum of...
