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# Pipelines, Piping and Fluid Mechanics engineering FAQ

## Flow in Pipe

 Spreadsheet for Friction Factors by quark faq378-1237 Posted: 20 Apr 06 As I prepared an excel spreadsheet to calculate various friction factor expressions (both implicit and explicit), I thought to share it with you guys, not because it is too difficult to do this but to avoid wastage of your time in writing those lengthy expressions and also the subsequent wastage of time in finding out which brace() we missed out.ProcedureEnter values of Reynolds Number in æC4Æ and e/D in æF4ÆFor Churchill Equation, enter the code of A =POWER(-2.457*LN((POWER((7/C4),0.9)+(0.27*F4))),16) in æC16 and of B =POWER((37530/C4),16) in æC17ÆEnter the code of f =8*POWER(((POWER((8/C4),12))+(1/(POWER((C16+C17),1.5)))),(1/12)) in æC18ÆFor Sherghides equationA =-2*(LOG((F4/3.7)+(12/C4))) in æC30ÆB =-2*(LOG((F4/3.7)+(2.51*C30/C4))) in æC31ÆC =-2*(LOG((F4/3.7)+(2.51*C31/C4))) in æC32ÆAnd f =POWER((C30-((POWER((C31-C30),2))/(C32-(2*C31)+C30))),-2) in æC33ÆFor Moody EquationF =(5.5/1000)*(1+(POWER(((2*10000*F4)+(1000000/C4)),1/3))) in æC39ÆFor Wood Equationa =-1.62*(POWER(F4,0.134)) in æC46Æand f =((0.094*(POWER(F4,0.225)))+(0.53*F4)+(88*(POWER(F4,0.44))*(POWER(C4,C46)))) in æC47ÆFor Jain Equationf =1/(POWER((1.14-(2*LOG(F4+(21.25/(POWER(C4,0.9)))))),2)) in æC54ÆFor Chen EquationA =LOG(((POWER(F4,1.1098))/2.8257)+(5.8506/(POWER(C4,0.8981)))) in æC62Æf =1/(POWER((-2*LOG((F4/3.7065)-(5.0452*C62/C4))),2)) in æC63ÆFor Zigrang and Sylvester EquationA =LOG((F4/3.7)-((5.02/C4)*(LOG((F4/3.7)+(13/C4))))) in æC71Æf =1/(POWER((-2*LOG((F4/3.7)-(5.02*C71/C4))),2)) in æC79ÆFor Colebrook EquationEnter initial f value as 0.02 in æC85ÆAnd copy the following formulae =1/(POWER((-2*LOG((F4/3.7)+(2.51/(C4*(POWER(C85,0.5)))))),2)) in æD87Æ =1/(POWER((-2*LOG((F4/3.7)+(2.51/(C4*(POWER(D87,0.5)))))),2)) in æE87Æ =1/(POWER((-2*LOG((F4/3.7)+(2.51/(C4*(POWER(E87,0.5)))))),2)) in æF87Æ =1/(POWER((-2*LOG((F4/3.7)+(2.51/(C4*(POWER(F87,0.5)))))),2)) in æG87Æ =1/(POWER((-2*LOG((F4/3.7)+(2.51/(C4*(POWER(G87,0.5)))))),2)) in æH87ÆGenerally G87 and H87 will have equal values(i.e Colebrook's equation generally converges after 4th step of iteration) and this is your friction factor for the given Re and e/DOnce you are done with making the spreadsheet, you can safely delete all those redundant rows from the spreadsheet.Please let me know in case of any technical problem. Back to Pipelines, Piping and Fluid Mechanics engineering FAQ Index Back to Pipelines, Piping and Fluid Mechanics engineering Forum

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