calculation of polar inertia of a half circle crosssection
calculation of polar inertia of a half circle crosssection
(OP)
sorry i am a bit rusty here. i need to know the J - polar inertia moment of a half circular body with thickness 't' around an axis that crosses at the half circle center (the circle's center.
ta
guy
ta
guy





RE: calculation of polar inertia of a half circle crosssection
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RE: calculation of polar inertia of a half circle crosssection
J = t^3*2r (units L^4)
or
J = t*PI*r^3 (units L^4)
depending on how conservative you want to be.
Cheers,
-- drej --
RE: calculation of polar inertia of a half circle crosssection
RE: calculation of polar inertia of a half circle crosssection
According to Roarks 5th edition stress and strain the formula for an open circular section in torsion is given as:-
J= (2/3)*pi*r*t^3
where r = mean radius
t = thickness
regards desertfox [2thumbs up]
RE: calculation of polar inertia of a half circle crosssection
RE: calculation of polar inertia of a half circle crosssection
Philrock: i am welding a fitting with a half pipe shape to a round pipe. so i guess we are still in the traditional approach. Thanks.
Guy