Formula for efficiency improvement
Formula for efficiency improvement
(OP)
I have to produce 2 kind of products in one batch(product "a" and product "b")
If I produce only "a", the batch will be finished in T1 hours; If only "b" is produced, the batch wil be finished in T2 hours. But I have to produce "a" anb "b" in the same time.
I'm trying to find out what in the most efficient combination "a" and "b"(how many "a" and how many "b"to place in the batch,(to get a minimal finish time)and what is the optimal "a+b"( between 50 and 100 pcs)
Have any idea if is a formula, or by graph.?
Thank you,
Doinel Blaj
If I produce only "a", the batch will be finished in T1 hours; If only "b" is produced, the batch wil be finished in T2 hours. But I have to produce "a" anb "b" in the same time.
I'm trying to find out what in the most efficient combination "a" and "b"(how many "a" and how many "b"to place in the batch,(to get a minimal finish time)and what is the optimal "a+b"( between 50 and 100 pcs)
Have any idea if is a formula, or by graph.?
Thank you,
Doinel Blaj





RE: Formula for efficiency improvement
T(final)= 1/(1/T1 + 1/T2 + ....+ 1/Tn)
RE: Formula for efficiency improvement
I think this equation is for combining paralell events, such as Valve A empties Tank in T1, Valve B empties Tank in T2, how long will both valves take to empty Tank. I can't see how it fits this situation, but just because I can't see it doesn't mean it doesn't.
Doinel,
I think we need to know more about what is driving this inquiry. What determines the number of a and b components you need in a given time period? Is the T1 and T2 figure the run times on a single machine or a series of machines? What size batch are the times for. Can the machine be run without any set up required when changeing from a to b?
RE: Formula for efficiency improvement
This is about making acrylic shells using a laser mashine.The input is variable. Let say the quantity of "a" product is 50 pcs.The machine will finish them in 3.5 hours ( if we process only "a").If only "b" product is 50 pcs., the machine will finish them in 6 hours.But in reality we have to combine "a" and "b" in the same batch and in the same machine.What I have to find out is the maximum input (up to 100 pcs. "a+b") and minimum process time.
Doinel
RE: Formula for efficiency improvement
It seems to me that you haven't given us nearly enough information.
What actually happens in the machine? Is there a single laser that must shine on each part in turn, or are there multiple lasers?
If there is only a single laser, I think the answer is 9.5 hours.
RE: Formula for efficiency improvement
Your problem as stated is a simple linear combination. The minimum time is to run only "a", which takes 7 hrs/100pc to running all "b", which takes 12 hr/100pc and the time is linear between those two points.
TTFN
RE: Formula for efficiency improvement
RE: Formula for efficiency improvement
RE: Formula for efficiency improvement
RE: Formula for efficiency improvement
If you know this classic example, the idea is that a society can produce x amount of guns or y amount of butter, but when you produce one, you reduce the amount of the other you can produce. For the sake of simplicity, I will assume doinel's earlier statement of production time is constant, meaning the first part of one type takes the same time as the last part and every part in between. The only function left is the value function, meaning the first part is more valuable than the last part. This leaves you with a solvable set of simultaneous equations.
$ = (cost function of x)(x) + (cost function of y)(y)
hours = x/(x parts/hr) + y/(y parts/hr)
The cost function is commonly a step function, like a customer needs 20 of x and will pay $$$ for them, but another customer needs 50 and will pay $ for them, hence the first 20 are worth $$$, 21-70 are worth $ and 71+ are worth 0. As you can see, this becomes a sum function