Hi All I need help in the calcul
Hi All I need help in the calcul
(OP)
Hi All
I need help in the calculation of dielectric loss (W/cm3) when subjected to a 50Hz AC supply. ie 4kV/mm. Assume a tan delta value.
Thanks in advance
I need help in the calculation of dielectric loss (W/cm3) when subjected to a 50Hz AC supply. ie 4kV/mm. Assume a tan delta value.
Thanks in advance






RE: Hi All I need help in the calcul
tan delta is a measurement of imperfection of a dielectric medium (ratio of watt losses-imperfection- to var reading-perfect dielectric represented by a capacitor)
just like calculating VAR, W and VA from power triangle, use tangent of angle delta. Assume VAR producing capacitor is parallel with W producing resistor. (in order to find these 3 values, you need to have another reading with tan delta value, VAR value maybe).
divide the calculated total W loss by the volume of the dielectric (assuming uniformity)
hope this helps
RE: Hi All I need help in the calcul
Are you familier with any formula for the loss calculation.
Thanks
RE: Hi All I need help in the calcul
http://www.qsl.net/wb6tpu/si-list/att-0017/01-I-k.PDF
http://canopus.physik.uni-potsdam.de/~s_bange/programs/...
(postcrip file)
http://www.cst.de/company/news/press/MWJournal_Aug_2002...
http://www.emf.eei.uni-erlangen.de/Aktuelles/Fischer/pd...
etc. for more info
RE: Hi All I need help in the calcul
To calculate di-electric loss one has to use formula
dielectric loss in watts = 2*3.142*f*c*v*v*tan delta
RE: Hi All I need help in the calcul