Spring Design û Change in Diameter with Compression
Spring Design û Change in Diameter with Compression
(OP)
Hi Guys,
A handbook I’ve got states that a spring has a 3-4% change in diameter when compressed.
I want to fit this spring in a fairly tight hole.
Does anyone know how the change in diameter is calculated?
I seem to recall that there was nifty little formula but I cannot find it.
Can any one help?
Thank you,
J
A handbook I’ve got states that a spring has a 3-4% change in diameter when compressed.
I want to fit this spring in a fairly tight hole.
Does anyone know how the change in diameter is calculated?
I seem to recall that there was nifty little formula but I cannot find it.
Can any one help?
Thank you,
J





RE: Spring Design û Change in Diameter with Compression
I´ve also learned a lot of formulas about such stuff, but in the end its only important that it works. For ´springs´ you probably want to use, you just multiply the nominal OD with 1,166667 and round up the result on one place after the comma.
regards,
MT
RE: Spring Design û Change in Diameter with Compression
http://www.daytonprogress.com
RE: Spring Design û Change in Diameter with Compression
http://www.efunda.com/designstandards/sp...
I don't know if they have the information you need but they have a lot on spring calculations.
RE: Spring Design û Change in Diameter with Compression
For a compression spring which has ends that are prevented from unwinding during compression the formula for expansion on diameter is as follows:-
change in dia= 0.05 * (p^2-d^2)/D
where d = wire dia
D = mean dia of coils
p = pitch of the coils when spring is in its
free state
formula represents spring going from free height to solid
length.
regards desertfox
RE: Spring Design û Change in Diameter with Compression
J
RE: Spring Design û Change in Diameter with Compression
RE: Spring Design û Change in Diameter with Compression
We use the old DOS version of the SMI software. A bit clunky, but the math is solid. The v5 software had some programming errors that made it worse than useless, but v6 is supposed to have fixed that.
RE: Spring Design û Change in Diameter with Compression
Alternative version of the formula above (from an Italian Spec....don't ask):-
change in dia = p^2-d^2/20D
and
change in dia = p^2-0.8d^2pd – 0.2 d^2/10D
Units would be s.i. (metric)
I have a demo copy of Institute of Spring Technology (IST) Spring Software....it is better than say the formulas/calculators on Efunda, the Engineerstoolbox and anything else I've found on the web by far...it is also cheap (not that i've bought it yet) but it is modular...and generally whatever i seem to want isn't on the modules on the demo.
Their website is www.ist.org.uk
I don't know if this is the same as the the SMI software.
J
RE: Spring Design û Change in Diameter with Compression
Take into consideration the following:
1. A spring is not a precision product. The coils may have a slight lateral shift (especially the end coils).
2. There is a commom tolerance on the outside diameter if you want to keep the price reasoable.
3. Even in a squared and ground spring the axis of the spring may have a +/- 3 degrees of tilt.
4. The spring axis is rarely a straight line it usually has a curve shape which increase with the increase of the load.
RE: Spring Design û Change in Diameter with Compression
Cost reduction is my aim and I am hoping to reduce the number of parts in an existing assembly. Currently, I have a two springs in a blind hole, which apply a pre-load. There is also a rubber ‘o’ ring; elsewhere; which also provides some pre-load. (The ‘o’ ring was a latter fix).
What I want is one spring to replace all three parts.
Ideally without changing the part where it fits.
Consequently, I need a spring of sufficient rate to provide the required load. However, this could (and did) mean increasing the diameter of the spring slightly.
I was concerned that a larger spring, when compressed, might jam in the hole. Thus, wanted to establish how much the diameter will increase.
Btw – I’ve got a spring that I want now
RE: Spring Design û Change in Diameter with Compression
I used www.smalley.com but there are a bunch of others
Keep the wheels on the ground
Bob
showshine@aol.com
RE: Spring Design û Change in Diameter with Compression
So, that brings me back to this thing:
change in D= 0.05 * (p^2-d^2)/D
If pitch is units of 1/L, then this isn't math. If its in L per turn what are the units?
Also, the expansion is surely a function of compression from free length.
Any clarification is appreciated.
RE: Spring Design û Change in Diameter with Compression
O.D.(at solid)=SQRT(D*D+(P*P-d*d)/(Pi*Pi))+d
D=spring mean diameter with no load
d=wire diameter
p=coil pitch
Pi=3.1416...
The spring outside diameter at no load=D+d
The difference O.D.-(D+d) is what you are looking for.
RE: Spring Design û Change in Diameter with Compression
www.ist.org.uk sell their "base module" for $167 and $335 for the Design module. There is also a Graphics module for pretty pictures(also $167)
J.
RE: Spring Design û Change in Diameter with Compression
But never has a problem with tight hole problem. IF you are trying to use the spring for other then producing force I think that approach is risky, If you design the surrounding of the spring too then I am sure you can make adjustments (enlarge the hole).
If you are trying to fit a spring into a hole and you can not increase the hole, I can try to design a spring for you to meet your demands. There are many ways you can try. You can switch to a stronger wire or you can design a spring with preset, etc.
If you can define your problem more accurately I may help you.
israelkk2001@yahoo.com
http://www.webspawner.com/users/israelkk/
RE: Spring Design û Change in Diameter with Compression
http://www.hexagon.de
RE: Spring Design û Change in Diameter with Compression
phil
RE: Spring Design û Change in Diameter with Compression
I've got a compression spring now.
But I've never heard of uratane.
Jalipa
RE: Spring Design û Change in Diameter with Compression
RE: Spring Design û Change in Diameter with Compression
The best way to go with a constant force spring is with a Bellevile spring. When the spring height divided by the thickness of the material is 1.41 than you have a region of constant force. More data such as:
1. Inside diameter of spring
2. Outside diameter of spring
3. The spring displacement during work (where you want the constant force
4. The force of the spring
is needed.
With this type of spring the variations in the outside diameter might be smaller.
In the past I have designed and built Bellevile Snap (Bi- stable) springs which have two stable positioned. Some were for 2 to 10 kg force and some were for 250 kg force.
I can check if a constant force spring can be done if you can provide the info.
israelkk2001@yahoo.com
http://www.webspawner.com/users/israelkk/