AC inverter rated motor
AC inverter rated motor
(OP)
My question is: I have a centrifuge that will spin a 10 inch diameter drum that weighs 20 lbs at 6000 rpm it can take up to 10 seconds to get up to speed..What HP motor do I select?? What is the equation for this??





RE: AC inverter rated motor
WK^2 = weight*(r^2/2 + r^2/2) for a hollow cylinder. Not quite true here but should be a good estimate.
wk2=20*(.4166)^2 = 3.47#ft^2
Tq to accel = (wk2 * delta rpm)/(308 * time in sec)
Tq= (3.47*6000)/(308*10) = 6.77 #ft
HP = Tq*base speed/5250 = 6.77 * 6000/5250 = 7.74HP
This assumes no losses and that the 6000rpm is the base speed of the motor. Especially note it did not include the HP required to accel the motor itself. So if you found a 10HP, 6000rpm motor, it should work.
Note if you go to a lower base speed motor and gear up, you still will require 7.74 for the centrifuge, you still have to include the motor and you will also have to include any gearing. By choosing 6000 rpm, I was saying it was direct geared, although this is not likely.
RE: AC inverter rated motor
RE: AC inverter rated motor
RE: AC inverter rated motor
Thanks for your help
RE: AC inverter rated motor
T[lb-ins]x[ft/(12xin)]=w[rad/sec]xP[Watts]x[HP/(746xWatts)]