pumping 16 cumecs
pumping 16 cumecs
(OP)
We are wanting to pump water into a race for a whitewater kayaking course. (16 cubic metres per second)
We want to lift the water 5 metres from a deep river.
Then the water will pour into a pool and flow into the race.
I want to Know
pump size
electricity usage
This is for costings per hour for our submissions work.
Cheers
Sam
We want to lift the water 5 metres from a deep river.
Then the water will pour into a pool and flow into the race.
I want to Know
pump size
electricity usage
This is for costings per hour for our submissions work.
Cheers
Sam





RE: pumping 16 cumecs
P = (w x Q x H)/(102 x Eff)
Where P = Power in kW
w = specific weight of liquid being pumped (for water it is 1000Kg/M3)
Q = discharge in M3/Sec
H = Differential head in meters
Your suction lift is 5 meters and I assume you are immediately discharging the water into the pool without any lift in the discharge. So I am considering total head of the pump at 7 meters (2 meters for losses)and considering pump efficiency of 60%.
Therefore, P = 1000 x 16 x 7/(102 x 0.6) = 1830 kW. This is the brake horse power. Now motor has it's own inefficiency. Considering 80% motor efficiency
Motor power = 1830/0.8 = 2287 kW
Best Regards,
RE: pumping 16 cumecs
The other potential is Flowserve's BSV, which is a vertical mixed flow pump with a concrete volute. Website is www.fpdlit.com/cms/results_detail.asp?ModelID=6
You might also want to try posting in the "Mechanical Engineers - Pump Engineering" forum, lot of guys there who may have seen this kind of flowrate before.
RE: pumping 16 cumecs
I will look at the websites suggested and go on from there.
The formula looks simple enough to use.
I'll be in touch
Sam
RE: pumping 16 cumecs
RE: pumping 16 cumecs
Naresuan University
Phitsanulok
Thailand
RE: pumping 16 cumecs
www.giwindustries.com is another website
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RE: pumping 16 cumecs
Naresuan University
Phitsanulok
Thailand