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Energy in compaction tests

Energy in compaction tests

Energy in compaction tests

(OP)
Dear all,
Does anybody know how to calculate energy per unit volume of soil induced in standard proctor compaction test. I know the amount of the energy but could not find out how to get that number. I need this information as I am compacting my soils using different number of blows, number of layers and different hammers. I would be glad if anybody can help me. Thanks a lot.

Regards
Agus

RE: Energy in compaction tests

dear agus,

i think the following might help u....

compaction energy (kJ) = {(mass of soils used, kg)x(number  
                           of blows)x(24.5N, which is your  
                           compaction rammer)x(height of
                           drop, m)}
                         __________________________________
                         {(volume of mould, cubic meter)
                           x1000)}
and your answer would be in kilojoule per cubic meter.

RE: Energy in compaction tests

The Standard Proctor D698 Energy is 12,375 foot pounds of energy per cubic foot.  It is simply the multiplication of 5.5 pound hammer times 1 foot drop times 75 drops divided by the volume of the mold which is 1/30 cubic foot.  This equates to 12,375.  The modified effort D1557 test is 10 lbs times 1.5 feet times 125 blows per 1/30 cubic foot of soil or 56,250 ft-lbs energy/cubic foot of soil.

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