Determination of ID and OD at Cryogenic Temperatures
Determination of ID and OD at Cryogenic Temperatures
(OP)
I have a 316 SS tube with an I.D. of 0.43″ and O.D. of 0.5 ″. Could someone please advise me on how I would calculate the I.D. and O.D. of the tube at cryogenic temperatures? The linear thermal expansion percent (L – L293/L293) at a temperature range (0 K – 300 K) is the only material property that I have access to. Thank you!





RE: Determination of ID and OD at Cryogenic Temperatures
NIST publishes good low temp CTE data. It isn't linear.
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P.E. Metallurgy, Plymouth Tube
RE: Determination of ID and OD at Cryogenic Temperatures
another day in paradise, or is paradise one day closer ?
RE: Determination of ID and OD at Cryogenic Temperatures
I perhaps should have asked, if the percent change in the length of the tube for a given temperature difference is the same as the percent change in its diameters individually?
RE: Determination of ID and OD at Cryogenic Temperatures
another day in paradise, or is paradise one day closer ?
RE: Determination of ID and OD at Cryogenic Temperatures
If the cross-section were to contract with the expansion in length, would the Poisson's ratio figure in the expression?
RE: Determination of ID and OD at Cryogenic Temperatures
The tube will get larger in diameter, thicker wall, and longer as it gets hotter.
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P.E. Metallurgy, Plymouth Tube
RE: Determination of ID and OD at Cryogenic Temperatures
Based on your statement, will the below expressions suffice? Thank you.
OD (Temp) = OD (293) + alpha (Temp)
ID (Temp) = ID (293) - alpha (Temp)
RE: Determination of ID and OD at Cryogenic Temperatures
another day in paradise, or is paradise one day closer ?
RE: Determination of ID and OD at Cryogenic Temperatures
so CTE x delta T x original size = change in size
I believe that the NIST formula is a 5th order fit.
http://cryogenics.nist.gov/Papers/Cryo_Materials.p...
http://www.dtic.mil/dtic/tr/fulltext/u2/438718.pdf
But this one has curves (not equations).
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P.E. Metallurgy, Plymouth Tube