Stack-up concept
Stack-up concept
(OP)
I would like to get a little help in understanding the stackup concept on the cases below. I have a hard time grasping the concept on how the X maximum and X minimum are to be CORRECTLY calculated (maximum and minimum distance between OD and ID). The numbers (X max. and x min.) are just all over the spectrum....
I have studied some of the examples found on eng.-tips, but looks like none of the existing shown cases are helping. Just some small tips and tricks on how to judge or think them would be really needed.
Thank you
Ani
I have studied some of the examples found on eng.-tips, but looks like none of the existing shown cases are helping. Just some small tips and tricks on how to judge or think them would be really needed.
Thank you
Ani





RE: Stack-up concept
RE: Stack-up concept
Case a.) position Ø3 MMC to A LMB
X min: (49 (LMC) -1 (form error) - 30 (LMC) -4 ( pos. 3 and bonus 1) )/2 = 7
X max: (50 (MMC) – 29 (MMC) +3 (pos.) ) /2 = 12
Case b.) position Ø3 to A LMB
X min: (49 -1 – 30 -3 (only pos. but no bonus ) ) /2 = 7.5
X max: (50 (MMC) – 29 (MMC) +3 (pos.) ) /2 = 12
Case c.) position Ø3 LMC to A MMB
X min: (49-1 -30 – 3 (only pos. no bonus at LMC available) )/2 = 7.5
X max: (50 (MMC) - 29 (MMC) +3 (pos.) + 1(bonus) ) / 2 = 12.5
What am I missing? Which calculation is incorrect?
RE: Stack-up concept
John-Paul Belanger
Certified Sr. GD&T Professional
Geometric Learning Systems
RE: Stack-up concept
Not really sure how to use it.
I appreciate your help.
Thank you
Ani
RE: Stack-up concept
You may not be familiar with that format of doing stacks (it already halves each diametric number as entered, rather than the final answers). But the thing you were missing is shown on the row called "shift." It has to do with the datum feature deviating from the prescribed boundary (MMB or LMB).
I must emphasize that these calculations are solving for a consistent wall thickness. If we wanted to know the max/min wall thickness at any possible cross-section then the answers would be different (because perfect form is not required at LMB, but for now let's skip it).
John-Paul Belanger
Certified Sr. GD&T Professional
Geometric Learning Systems
RE: Stack-up concept
I should have remembered this from the similar question that began on this forum on Sept. 8!
I've changed the spreadsheets and reattached them here. Somebody let me know if it still doesn't look right.
John-Paul Belanger
Certified Sr. GD&T Professional
Geometric Learning Systems
RE: Stack-up concept
Thank you for the corrected Excel file!
My follow up questions:
On case A, why the form error on datum feature A is not conisdered, otherwise speaking why the answer is not driven from 48, but from 49 (LMC)?
On case B, again, the driving term, per your spreadsheet is 49. Why not 48 since the form error is to be considered as the perfect form at MMC is enforced (not the perfect form at LMC). Am I correct?
Case C, is the only one in agreement. Interesting fact, I considered form error on datum feature A on all three cases, but you didn't and even that we got on case C same result. Go figure. !
RE: Stack-up concept
(a): max = 13; min = 7
(b): max = 13; min = 7
(c): max = 12.5; min = 7.5
pylfrm
RE: Stack-up concept
May I ask, your calculations are in the consistent wall thickness scenario (described by J-P) or the absolute min/max in any possible cross section case?
Thank you for your input
RE: Stack-up concept
Merry Christmas Ho! Ho! Ho!
RE: Stack-up concept
I basically assumed a tube of infinite length, in which case I don't believe there's a difference.
I will also note that form error is only required for the minimum wall thickness of case (b). The other five values can be achieved without form error.
pylfrm
RE: Stack-up concept
Also, I'm not sure what you mean when you write that "form error is only required for the minimum wall thickness of case B."
John-Paul Belanger
Certified Sr. GD&T Professional
Geometric Learning Systems
RE: Stack-up concept
The calculations may change, but not the results. The equivalence is discussed in thread1103-430008: Stackup RFS-MMC combo, simple part, same results?.
With a perfectly cylindrical hole, every point on the surface will be within 15.0 of the feature axis. The smallest possible wall thickness in case (b) would be 7.5. Introducing form error to the hole allows the surface to be 15.5 away from the feature axis in one direction, reducing the wall thickness to 7.0.
The LMB being 48 instead of 49 affects the minimum wall thicknesses as well as the maximums, but I don't believe you accounted for that in your revised spreadsheets. That should explain the rest of the difference between your answers and mine.
pylfrm
RE: Stack-up concept
In the meantime I'll read that other thread; I never really went through it when it popped up back in September.
John-Paul Belanger
Certified Sr. GD&T Professional
Geometric Learning Systems
RE: Stack-up concept
No, I stand by my original answers. I was just trying to explain my earlier comment about form error. If OP's question were modified to require perfect cylindricity on the ID and OD, then the answers would be the following:
(a): max = 13; min = 7
(b): max = 13; min = 7.5
(c): max = 12.5; min = 7.5
The only one that changes is the minimum for case (b).
As for the spreadsheet inputs, I'd say you need to add 0.5 of shift to the case (a) and (b) minimum calculations to account for the difference between the datum feature size you used (49) and the LMB (48). You also need to change the "axis of ID / edge of ID" value for the case (b) minimum calculation from 15 to 15.5 to include the effect of form error.
Perhaps thread1103-426288: Form error in the stackup calculation would actually be more useful. Nescius posted a good illustration.
pylfrm
RE: Stack-up concept
edit (adding a comment): It's also good to note that this stack question would seem to yield a different answer if the position symbol were changed to concentricity (ASME style). Just about every stack textbook says that position and concentricity are treated the same way in a stack, but Nescius's picture shows the difference (position is based on the AME and concentricity would be based on the median points).
RE: Stack-up concept
Could you, please attache/ post a sketch (similar to Nescius's picture) on how YOU came up with the values shown above?
"(a): max = 13; min = 7
(b): max = 13; min = 7
(c): max = 12.5; min = 7.5"
You know a picture worth a thousand of words. I appreciate your help.
Thank you
Ani
RE: Stack-up concept
I agree. It would be helpful for me too.
Thank you pylfrm.
RE: Stack-up concept
I'm not feeling terribly inspired to draw circles at the moment. Perhaps if you post your own sketches, I (or someone else) can provide some further insight.
pylfrm
RE: Stack-up concept
http://files.engineering.com/getfile.aspx?folder=b...
RE: Stack-up concept
Happy New Year !
RE: Stack-up concept
RE: Stack-up concept
RE: Stack-up concept
The only thing I can add is to note that the minimum and maximum can both exist simultaneously on a single part for each case.
pylfrm