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# (Applied Thermodynamics)__How to calculate the specific volume of water, at 100ºC and 1.5 bar?3

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## (Applied Thermodynamics)__How to calculate the specific volume of water, at 100ºC and 1.5 bar?

(OP)
The only data in the question is this table:

Do we have to do an interpolation between the point at 100ºc + 1.014 bar, the point at 110ºC+ 1.433 bar, and the point at 120ºC + 1.985 bar ?

What other suggestions you may have?

Thanks a lot!

### RE: (Applied Thermodynamics)__How to calculate the specific volume of water, at 100ºC and 1.5 bar?

2
I'd use 1.0435x10-3 m3/kg from the sat'd 100o C liquid. The change in density/specific volume on a liquid (water) by compressing it from 1.014 bar to 1.5 bar is nil.

Good luck,
Latexman

To a ChE, the glass is always full - 1/2 air and 1/2 water.

(OP)
Thanks guys!!

### RE: (Applied Thermodynamics)__How to calculate the specific volume of water, at 100ºC and 1.5 bar?

NIST gave sat'd properties density = 958.35 lb/m3 and 1.5 bar isobaric properties density = 958.37 lb/m3.

Good luck,
Latexman

To a ChE, the glass is always full - 1/2 air and 1/2 water.

### RE: (Applied Thermodynamics)__How to calculate the specific volume of water, at 100ºC and 1.5 bar?

Steamtab
You need not look in to a table, again, once you download this.

### RE: (Applied Thermodynamics)__How to calculate the specific volume of water, at 100ºC and 1.5 bar?

From NIST webbook. 0.0010434 m3/kg.

### RE: (Applied Thermodynamics)__How to calculate the specific volume of water, at 100ºC and 1.5 bar?

An alternate method is to use a steam Mollier diagram since it will show the specific volume lines in the superheated region. You may have to interpolate and loose a little accuracy.

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