## Div-2 Part.5 Protection against plastic collapse

## Div-2 Part.5 Protection against plastic collapse

(OP)

Dear All,

I am using ASME BPVC Sec. VIII-2 for my design by analysis. I faced difficulty while I tried to interpret the criteria provided by the code for protection against plastic collapse. The formulas are as follows:

P

P

P

What I cannot understand is that why both equations 5.3 and 5.4 shall be satisfied? I mean if equation 5.4 is satisfied then it seems that equation 5.3 is satisfied automatically.

The second question is that what happens if the secondary plus primary stresses exceed S

Warm Regards

I am using ASME BPVC Sec. VIII-2 for my design by analysis. I faced difficulty while I tried to interpret the criteria provided by the code for protection against plastic collapse. The formulas are as follows:

P

_{m}<=S (5.2)P

_{L}<=S_{PL}(5.3)P

_{L}+P_{b}<=S_{PL}(5.4)What I cannot understand is that why both equations 5.3 and 5.4 shall be satisfied? I mean if equation 5.4 is satisfied then it seems that equation 5.3 is satisfied automatically.

The second question is that what happens if the secondary plus primary stresses exceed S

_{PS}? Is that a kind of failure or is it not important at all?Warm Regards

## RE: Div-2 Part.5 Protection against plastic collapse

I will try to answer your first question using para. 5.2.2.2 of VIII.2 i.e. STRESS CATEGORIZATION. Looking at Equations 5.3 & 5.4 simultaneously they might look like mathematical equations, but they are not. Please refer stress categories listed in para. 5.2.2.2 (a), (b) and (c).

Pis the equivalent stress, derived from ---, of the_{L}localprimary stresses andPis the equivalent stress, derived from --- of the linearized_{L}+P_{b}general or localprimary membrane stressesplus primary bending stresses. Meaning membrane in later category (P_{L}+P_{b}) can be general or local. It's all the way separate stress category depending upon stress location under evaluation (i.e. region where stress classification line is). Reading paragraphs 5.2.2.2 (a),(b)and(c) in conjunction with Table 5.6 (which provides guideline @ relation between location and type of stress) and Figure 5.1 may help in better fashion.The second question is that what happens if the secondary plus primary stresses exceed S

_{PS}? Is that a kind of failure or is it not important at all? - it is failure, since S_{PS}addresses primary as well as secondary stresses (refer para. 5.5.6.1 (c))and not only secondary stresses which can redistribute themselves not causing failure and that's why code wants it within allowable.Hope this helps.

## RE: Div-2 Part.5 Protection against plastic collapse

With all of your DBA questions, I would highly recommend taking a course. A Google search of ASME Section VIII, Division 2, Part 5 training should highlight some suitable options.

## RE: Div-2 Part.5 Protection against plastic collapse

PVDEngg,So if I get you right PL + Pb is not the sum of two equivalent stresses rather, PL+Pb is the equivalent stress derived from the sum of two stress tensors.TGS4,I have doubt regarding ratcheting criterion in 5.5.6.1.(d) The allowable limit on the primary plus secondary stress range, S P S, is computed as the larger of the quantities shown below.

(1) Three times the average of the S values for the material from Annex 3-A at the highest and lowest temperatures during the operational cycle.

(2) Two times the average of the Sy values for the material from Annex 3-D at the highest and lowest temperatures during the operational cycle, except that the value from (1) shall be used when the ratio of the minimum specified yield strength to ultimate tensile strength exceeds 0.70 or the value of S is governed by time-dependent properties as indicated in Annex 3-A.

The allowable stress (Div.2) is given by:

S=min{Sy/1.5, Su/2.4}

Multiplying by 3 gives:

3S=min{2Sy, 0.833Su}

Now, here it can be seen that 2Sy is either more than 3S or equal to that. Therefore, the larger of these two values is going to be 2Sy.

Only in special cases where S can be higher than Sy/1.5 (Note G2 of table 5A SecII-D) in which S may be as high as 0.9Sy. It means that the SPS can be as high as 3*0.9*Sy=2.7Sy.

To my eyes if linear elasticity is showing stresses (primary plus secondary) higher than 2Sy ratcheting is inevitable. Even if there is residual compressive stresses with magnitude equal to Sy, there will be plastic strain and no elastic shakedown will occur.

## RE: Div-2 Part.5 Protection against plastic collapse

The only current concern about the VIII-2 ratcheting limits is that S

_{ps}can occasionally be greater than S_{u}, which is generally not reasonable/appropriate.