The method of find out the actual leaving air temperature of cooling apparatus, here an example takes an FCU. The chilled water entering temperature 47F, bypass factor .20 and entering air temperature is 75F. Please see the calculation as per the psychometric formula Tldb=Tadp+bf(Tedb-Tadp), then 47+.02(75-47)=52.6F( 11.4C) is it practical in field?
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