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# cooling system

## cooling system

(OP)
Hi everyone,
I am trying to design a cooling system, which contains a big container inside it static fluid, and I have to design pipes go through the big container,the pipes should have cold liquid inside it and this liquid has velocity, I know for the pipes I have to use the following formula:
q= m*cp*(T1-T2)
My question is how can include the material of the pipe which should be important? because the previous formula involve cp for the liquid only?
Amaar

### RE: cooling system

Any text with the title Process Heat Transfer will answer your question. The calculation of the overall heat transfer depends on three resistances. one of those resistances has the thermal conductivity of the pipe metal.

### RE: cooling system

its natural convection, the formula you just mentioned is not that...

### RE: cooling system

Actually, it's both; convection between the flowing fluid in the pipe to the pipe wall, conduction through the pipe wall, and convection from the outside of the pipe to the static liquid. The equation presented appears to be a Joule heating equation, which is a tiny portion of the overall problem.

Convection is of the form:
q = area*convection_coefficient*delta_temp

Conduction is of the form:
q = area*(thermal_conductivity/thickness)*delta_temp

q = mass*heat_capacity*delta_temp is used to determine the amount of heat to be removed. However, your large container has its own thermal losses, which include a convection-conduction-convection pathway, just like the pipe inside.

TTFN (ta ta for now)
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Keep it up.

### RE: cooling system

Ummm...what are you saying, elmafulk?

CR

"As iron sharpens iron, so one person sharpens another." [Proverbs 27:17, NIV]

### RE: cooling system

One equation and 5 unknowns.

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