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UDL on pulley from rope tension

UDL on pulley from rope tension

(OP)


A lot of posts, ifs, ahhhhs and opinions but no posts that seem to be able to point to an equation and go 'heres the equation'.

Theres the good ole 2T/Dd
Throwing some figures at it
(2 x 10,000) / (0.5x0.006) = 6.67 MPa
as a udl on say 135 deg angle of wrap and a 6mm rope squash width
F = PA = 6.67*(2*pi*0.5)*(135/360)*0.006 = 47 kN
as a UDL
47 / (2*pi*0.5)*(135/360) = 39.9 kN/m?

sound about right?... Thoughts?



RE: UDL on pulley from rope tension

(OP)
http://www.eng-tips.com/viewthread.cfm?qid=398642

but a browse of the responses is ...

I cannot directly assist you ...
I must admit I do not have extensive knowledge in this area....
i propose you seek out some sources on belt conveyor re belt pulley design for deeper insight....

The internet sigh... lol

RE: UDL on pulley from rope tension

You used the value of the radius of the pulley rather than the diameter, so divide your answer by 2.

RE: UDL on pulley from rope tension

(OP)
Compositepro

Cheers - mega thanks. Got a wishlist or something similar I can buy something for you, wine, spirits etc? :D

Test result on the disk came out the same. Had load cells in spokes to see if the approximation would meet the calculation. Came out real nice, (very close) and I got a pat on the back.

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