%mol - CO2
%mol - CO2
(OP)
Struggling with some very basic composition math...
I'm looking to calculate the percentage of CO2 in a volume flow based on %mol CO2.
Information is as follows:
Rate: 128,865 Nm3/hr
Composition (vol%): 4.3%mol CO2
Calculation:
Is it as simple as 128,865 * .043 =5,541 Nm3/hr - CO2.
Which can than be converted to kg/hr as follows:
5,541 Nm3/hr * 1977 kg/m3 ~= 10,955kg/hr
I'm looking to calculate the percentage of CO2 in a volume flow based on %mol CO2.
Information is as follows:
Rate: 128,865 Nm3/hr
Composition (vol%): 4.3%mol CO2
Calculation:
Is it as simple as 128,865 * .043 =5,541 Nm3/hr - CO2.
Which can than be converted to kg/hr as follows:
5,541 Nm3/hr * 1977 kg/m3 ~= 10,955kg/hr





RE: %mol - CO2
1562 kg/m3 (solid at 1 atm and −78.5 °C)
1101 kg/m3 (liquid at saturation −37°C)
1.977 kg/m3 (gas at 1 atm and 0 °C)
See what I mean?
Good luck,
Latexman
To a ChE, the glass is always full - 1/2 air and 1/2 water.
RE: %mol - CO2
Sorry, fat finger mistake. I was going for 1.977kg/m3.
RE: %mol - CO2
TTFN (ta ta for now)
I can do absolutely anything. I'm an expert! https://www.youtube.com/watch?v=BKorP55Aqvg
FAQ731-376: Eng-Tips.com Forum Policies forum1529: Translation Assistance for Engineers
RE: %mol - CO2
5541/22.414*44=
RE: %mol - CO2
and at 0 °C. At 1 bar, it would be ~ 22.711 L/mol.
RE: %mol - CO2
RE: %mol - CO2
RE: %mol - CO2
RE: %mol - CO2
SO2 21.856
H2S 22.187
CH4 22.361
O2 22.392
N2 22.404
Ne 22.425
H2 22.428
One can see the differences, however small, because of their cuasi-ideality at normal conditions..
RE: %mol - CO2
RE: %mol - CO2
CH4 44.722
SO2 45.755
and for n-butane
C4H10 46.518 (in this case the deviation from ideality is more than 4%)
RE: %mol - CO2
https://ens.dk/sites/ens.dk/files/OlieGas/oil_and_...
page 104
RE: %mol - CO2
Your statement would imply all real gases have the same Z compression factor, which is not the case.
RE: %mol - CO2
Is it sunny outside? No, I want a hamburger for dinner.
Dejan IVANOVIC
Process Engineer, MSChE
RE: %mol - CO2