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BS 4882 Fig 4 designation D - Problems

BS 4882 Fig 4 designation D - Problems

BS 4882 Fig 4 designation D - Problems

(OP)

Could do with some advice on the below problem I have.

BS4882 fig.4 D stipulates a double ended stud with a reduce portion retuning back to nominal diameter in the centre. The ends ae symmetrical!!

Here lies my problem

the equation uses the nominal diameter at a ratio to work out the thread length & the reduced portion length.

Lets say for instance for 1/2" Dia the total chamfer length + thread length + Reduced diameter length is 30mm,
What do I do if my stud dimensions given on my order are 1/2" x 56mm.

Do I sacrifice the reduced diameter or the thread length?

I am at a complete loss, anyone have ay advice or ideas?

Thanks

RE: BS 4882 Fig 4 designation D - Problems

Hi

I've looked at BS4882 and I would use the Imperial part for working the stud ratio's of diameter and length etc. because you are quoting 1/2" in your post.
Look at the notes on the bottom of page 30 relating to table 18 particularly notes a and b, I would ignore the 56mm length given in your post and supply a length of 1/2"x 2.5", incidentally 56mm = 2.25"

“Do not worry about your problems with mathematics, I assure you mine are far greater.” Albert Einstein

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