Reply to thread 406-282835
Reply to thread 406-282835
(OP)
Hello
I also am trying to find the maximum and minimum sizes over pins for an external DIN 5480 spline. I am using DIN 5480:2006 parts 1 and 2. In DIN 5480-1:2006 section 10.12 of this standard it talks about using DIN 5480-15 to calculate these sizes, this is not available to us. It also suggests that it can be done using the deviation factors as described in DIN 5480-2, however no explanation of how this is achieved is given.
In DIN 5480-1:2006 section 9.1 there is given an example of a W120x3x38x8f side fit spline. I have been trying to find M1max and M1min for this spline using the deviation factor. The target sizes from the example are Max 126.017, min 125.956.
DIN 5480-1:2006 section 10.12 tells us the deviation of the measurements over measuring circles is AM1=Ae*A*M1 = -0.04256
Obviously this isn't enough on it's own. So far the closest I have managed to come is to apply AM1 to the f8 limit dimensions of the 120 shaft i.e. -0.036/-0.090. This gives an answer of max 126.016, min 125.962.
I don't believe this is right, where am I going wrong?
I also am trying to find the maximum and minimum sizes over pins for an external DIN 5480 spline. I am using DIN 5480:2006 parts 1 and 2. In DIN 5480-1:2006 section 10.12 of this standard it talks about using DIN 5480-15 to calculate these sizes, this is not available to us. It also suggests that it can be done using the deviation factors as described in DIN 5480-2, however no explanation of how this is achieved is given.
In DIN 5480-1:2006 section 9.1 there is given an example of a W120x3x38x8f side fit spline. I have been trying to find M1max and M1min for this spline using the deviation factor. The target sizes from the example are Max 126.017, min 125.956.
DIN 5480-1:2006 section 10.12 tells us the deviation of the measurements over measuring circles is AM1=Ae*A*M1 = -0.04256
Obviously this isn't enough on it's own. So far the closest I have managed to come is to apply AM1 to the f8 limit dimensions of the 120 shaft i.e. -0.036/-0.090. This gives an answer of max 126.016, min 125.962.
I don't believe this is right, where am I going wrong?





RE: Reply to thread 406-282835
RE: Reply to thread 406-282835
Dk=6 (pin dia.)
Mdk=126,095
A*=1,52
8f: -0,051/-0,091
The min measurement: 126,095-0,091*1,52=125,96
The max measurement: 126,095-0,051*1,52=126,02
The same for the span measurement:
7 (no of teeth)
M7=59,710
A*=0,866
8f: same
The min measurement: 59,710-0,091*0,866=59,63
The max measurement: 59,710-0,051*0,866=59,67
RE: Reply to thread 406-282835
Thank you, that looks like what I am trying to find. Please can you tell me, where did you get the values for 8f? Is it the DIN 5480-15:2006 that I have not got?
RE: Reply to thread 406-282835
RE: Reply to thread 406-282835
Think I could have looked at this till the cows came home and never got it.