Working out the length and weight of a helical
Working out the length and weight of a helical
(OP)
I am trying to work out the lenght and weight of a helical in tonne on a steel rebar cage,
The diameter of the cage is 100mm,
The length is 5meter
And the pitch if the spirals is 100mm
I know this isn't much info but any help on the formula for this would be much appreciated
Thanks Karl
The diameter of the cage is 100mm,
The length is 5meter
And the pitch if the spirals is 100mm
I know this isn't much info but any help on the formula for this would be much appreciated
Thanks Karl





RE: Working out the length and weight of a helical
RE: Working out the length and weight of a helical
if possible could you explain the file,
what is the DN? also do you know the formula used?
Am i right in thinking it would be Diameter x Pi 3.14 to get the circumference.
Then length of cage divided by the pitch of the helical to work out number of turns.
Then circumference x No of turns to work out Total length x reinf weight (km/m) divided by 1000 to work out weight in tonne.
RE: Working out the length and weight of a helical
RE: Working out the length and weight of a helical
1 - for single cage the mid thickness
2 - double cage : inner cage 50 mm from inside wall of concrete
outer cage 50 mm from outside wall of concrete
What above to use or to modify the program.
For the rest : you are correct. If you look in detail I used the same formulas
RE: Working out the length and weight of a helical
For a single turn, the length is √((πD)2+p2). With the original data this produces an increase of 5%.
prex
http://www.xcalcs.com : Online engineering calculations
http://www.megamag.it : Magnetic brakes and launchers for fun rides
http://www.levitans.com : Air bearing pads
RE: Working out the length and weight of a helical
for the question, What is the weight of the helical on a 5 meter cage, the gage being 100mm o/d (diameter), 5 meters in length and the turns at 100mm pitch is this correct-
100mm (Diameter) x 3.14 = 314 mm
length 5000mm / 100mm (pitch) = 50 turns
314 x 50 = 15.700mm / 1000 = 0.0157 meters
0.0157 x (kg weight per meter) 0.222 = 0.0034854 kg/meter
0.0034854 / 1000 = total weight in tonne 0.00000349
the part i can't understand is the helical covers the full length of 5 meters, so how can the total length be anything under 5meter.
RE: Working out the length and weight of a helical
In your explanation there are mistake in transforming units : 15.7 are meters and not mm !!!!!!!
RE: Working out the length and weight of a helical