Fermat's Spiral - Sketch pattern creation
Fermat's Spiral - Sketch pattern creation
(OP)
Hi everyone,
I have an interesting design problem that at the moment is a little over my head in both solid works skills and mathematics knowledge.
I need to layout a sketch pattern / feature pattern in SolidWorks to create approx 8000 holes. The pattern of the holes follows the sun flower spiral, the layout of the seeds in a sun flower head. AKA Fermat's Spiral, this corresponds to Fibonacci numbers.
More on this can be viewed at:
http://en.wikipedia.org/wiki/Fermat's_spiral
http://ms.unimelb.edu.au/~segerman/papers/sunflowe...
Has anyone experience in this? or do you think it might be possible using equations?
Any help would be much appreciated.
Thanks
I have an interesting design problem that at the moment is a little over my head in both solid works skills and mathematics knowledge.
I need to layout a sketch pattern / feature pattern in SolidWorks to create approx 8000 holes. The pattern of the holes follows the sun flower spiral, the layout of the seeds in a sun flower head. AKA Fermat's Spiral, this corresponds to Fibonacci numbers.
More on this can be viewed at:
http://en.wikipedia.org/wiki/Fermat's_spiral
http://ms.unimelb.edu.au/~segerman/papers/sunflowe...
Has anyone experience in this? or do you think it might be possible using equations?
Any help would be much appreciated.
Thanks





RE: Fermat's Spiral - Sketch pattern creation
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RE: Fermat's Spiral - Sketch pattern creation
you need a scale factor for n in that equation otherwise it is messy (or use non integer n)
Cheers
Greg Locock
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RE: Fermat's Spiral - Sketch pattern creation
x[n]=numpy.sqrt(n*nscale)*numpy.cos(2.*pi*phi*n*nscale)
y[n]=numpy.sqrt(n*nscale)*numpy.sin(2.*pi*phi*n*nscale)
and
x1[n]=numpy.sqrt(n*nscale)*numpy.cos(2.*pi*n*nscale)
y1[n]=numpy.sqrt(n*nscale)*numpy.sin(2.*pi*n*nscale)
Cheers
Greg Locock
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