Von Mises Yield Criterion
Von Mises Yield Criterion
(OP)
Hi,
I've calculated the safety factor for the Von Mises Yield Criterion compared to the yield strength of the material. I got a safety factor of 1.075 which is very close to 1. I know that the material is about to fail.
However, is there a range of values that the safety factor can have? I found from an online source that the factor of safety should be in the range of 1.25-4. Is this true?
Is there anything we can do to increase the safety factor so that it is ensured that the material is not going to fail?
I will appreciate any help
Thank you
I've calculated the safety factor for the Von Mises Yield Criterion compared to the yield strength of the material. I got a safety factor of 1.075 which is very close to 1. I know that the material is about to fail.
However, is there a range of values that the safety factor can have? I found from an online source that the factor of safety should be in the range of 1.25-4. Is this true?
Is there anything we can do to increase the safety factor so that it is ensured that the material is not going to fail?
I will appreciate any help
Thank you






RE: Von Mises Yield Criterion
The greatest trick that bond stress ever pulled was convincing the world it didn't exist.
RE: Von Mises Yield Criterion
The FOS of 1.5 came from the old (Australian) steel design code before ultimate limit state was adopted.
A FOS of 1.075 is very low. That said, if you are comparing stresses from an FE model you need to look at the location of the stresses as you will get stress rises at T intersections, poor meshes, load locations & boundaries that may not be representative of the actual stress state.
If your stresses are not driven by thermal effects, extra material thickness should see stresses reduce.
RE: Von Mises Yield Criterion
RE: Von Mises Yield Criterion
RE: Von Mises Yield Criterion
The problem is that I haven't assumed a safety factor but I have derived it.
I have designed a shear wall made of reinforced concrete and I had to check if a particular point in the wall is going to fail. I was given the yield stress of the material (100 MPa) as well as the tensor matrix for that particular point. Based on the tensor matrix I have calculated the principal stresses so that the von mises stress can be obtained. The value of the von mises stress was 93 MPa. I have divided those two values to get the safety factor (100/93) and it gave me 1.075. What does that says to me?
RE: Von Mises Yield Criterion
The greatest trick that bond stress ever pulled was convincing the world it didn't exist.
RE: Von Mises Yield Criterion
Von Mises failure criteria is more for a ductile material (like steel).
RE: Von Mises Yield Criterion
RE: Von Mises Yield Criterion
of reinforced concrete structures, report No. 45, 2008.
RE: Von Mises Yield Criterion