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quick check calc

quick check calc

quick check calc

(OP)
If I have a rigid plate with a 240 inch-lb torque applied to it and I have two 1/8" holes each one spaced 1/2" (on centers) away from toque point on opposite sides of the torque, how much would my resistance force have to be at each hole (in inch-lbs) to resist the torque? Thanks!

RE: quick check calc

so there's 1" between the couple forces ... the answer's obvious, no?

another day in paradise, or is paradise one day closer ?

RE: quick check calc

assuming, of course, that there's no clamp-up, ie that some of torque is being reacted as a moment under the bolt heads.

another day in paradise, or is paradise one day closer ?

RE: quick check calc

Well it seems simple enough but I think a sketch might help clarify things

RE: quick check calc

(OP)
Agreed, it is super simple, its just those simple problems that sometimes make you think am I missing something?

RE: quick check calc

(OP)
http://physicsnet.co.uk/wp-content/uploads/2010/08/couple1.jpg

distance between s and each f is .500

RE: quick check calc

link didn't work ...

picture looks pretty useless (we don't hold back here).

it still looks like a couple with an arm of 1" ...

another day in paradise, or is paradise one day closer ?

RE: quick check calc

your link (at an A-levels site) makes me suspect a student post.

this is a professional site. student's should post at http://www.engineering.com/AskForum/aff/32.aspx

another day in paradise, or is paradise one day closer ?

RE: quick check calc

(OP)
easy there big guy. I couldn't post a photo from my phone so I just sent the url to a photo that would best represent it. it just happened to be on a student site.

RE: quick check calc

ok, but when you ask a really basic question and post very crude pix linked to a student site, i think it's understandable.

as i've said already, it still looks like a couple on a 1" arm ... so what's the question ??

another day in paradise, or is paradise one day closer ?

RE: quick check calc

(OP)
There are steel dowels in those 1/8" holes. If the torque of 240 in-lbs is applied to the center of plate, rigid plate, the force acting on each dowel pin is 240Lbf? Is it as easy as that, or am I missing something? Friction negligible.

RE: quick check calc

it's pretty much as easy as that !

your pic is showing shear on the dowels, with the torque veector being out-of-plane ... yes?
in which case the answer is correct.

another day in paradise, or is paradise one day closer ?

RE: quick check calc

(OP)
Thanks very much, sometimes it just seems too simple that I start overthinking it.

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