Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
(OP)
As I started plowing into the programming of my new web based MFWRS wind load calculator I decided to try and pick up as many roof types as possible. I'm intending to use the Envelope Procedure from Part 1 of Ch. 28 of the ASCE 7-10 so things are a bit limited with respect to building aspect ratio, height etc... Section 28.2 specifically states that one can use this method to analyze buildings that have gable, hip and flat roofs.
My question is can this method also be used to analyze Half Hip and Dutch Gable roofs which are essentially somewhere in between a Gable and Hip type roofs? Rationally it makes sense to me but just thought I might throw it out to the crowd for any comments or corrections.
The five possible roof types would then be:

My question is can this method also be used to analyze Half Hip and Dutch Gable roofs which are essentially somewhere in between a Gable and Hip type roofs? Rationally it makes sense to me but just thought I might throw it out to the crowd for any comments or corrections.
The five possible roof types would then be:







RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
(Just (half) kidding; there are a lot of sharp guys on this site and some of them will be able to help you.)
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
Notice also in the notes that one should use the coefficients from Table A for both Load Case A and B for a hip roof. Unfortunately, Table A is missing zones 5, 6, 5E and 6E.
I'm confused.
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
Why the change? Where can I find answers to the reason for the changes and an understanding on how to apply the proper coefficients to the hip roof.
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
I am going to ask the Chair of the ASCE 7-16 Subommittee on Wind Loads to weight in at this point since I cannot seem to find a reasonable explanation for these discrepancies within the ASCE 7-10.
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
Load Case A:
Load Case B:
If torsional load cases are required then another Load Case A and B are required for the torsional load case.
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
See, a "perfect" wind blowing "exactly from the perpendicular side" of a perfect house with perfect landscaping (no trees, hills, slopes, bushes, or valleys) "might" at "exactly" the assumed "per Code" wind requirements would likely produce the forces that you expect from the program, right?
But those conditions don't exist in the real world of non-PhD engineering.
So, how accurate do you need to be?
( Probably, accurate enough to keep the roof on under most storms, right?)
First Set. So, I would strongly recommend NOT using the "flat-top roof with square edged walls" (Figure 3 ? in the first set) to mimic any results that might come from the other 4 typical houses. A flat roof, combined with the risers surrounding the flat roof, have NOTING in common with the sloped roofs (or curved, or cambered or or multi-sloped hip roofs) that the other roofs in Set 1 have.
Second Set: The presence of a overhang in Set 2 is significantly different for ALL of the sloped roofs from the 4 sloped roofs in Set 1. Again, that overhang causes a significant INCREASE in local whipping/turbulent loads right at the roof edge, and ADDS the overhang distance on every side to the natural lever arm of the rest of the roof in "pulling up" the roof from the walls. The overhang, increases whipping (vibration) of the overhung rafter edges, and so the whole structure is more highly stressed from winds from any direction.
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
I agree wind loads, snow loads and even seismic loads are bit of fuzzy math in my opinion. Nothing makes this stand out more clearly in my mind than the changes to the envelope procedure in 2002 and then back to the 1998 version in 2010 (ASCE 7). I have no explanation for the change in the first place and then no explanation why the change back. Wind loads haven't changed just our perceived understanding of them or misunderstanding.
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
So racookpe1978 what are you suggesting with the way I'm analyzing the standard gable roof? I can understand your observations but what is the conclusion to draw from all of this?
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
As to your attempts to blend roof types to yield other roof types, while logical, is going to be hard to defend. Besides which the actual model will likely do things you'll find hard or impossible to predict. Whether a particular area is even negative or positive in pressure is not likely to be correct when combining models that don't have that area (the little vertical triangles on the Dutch Gable, as an example).
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
The Design pressure for this uplift would be calculated as P= qe * GCp at Load Case A since the overhangs are at the height of the eave height. For the gable overhangs I am calculating the Design Pressue using qh since the overhangs vary from eave height to ridge height.
Note that this is different from the Directional Procedure which as suggested above equates the windward overhang pressure to the wall pressure below (Sec. 27.4.4).
With the envelope procedure the max. windward wall pressure coeff. is GCpf = .56 in the interior regions (transverse case), which is different than GCp = .7.
For windward overhangs the total pressure becomes:
2EOH+W = (qh * CGpf2E) + (qe * GCp)
2OH+W = (qh * CGpf2) + (qe * GCp)
All other overhangs along the sides and leeward sides are simply the velocity pressure (qh) multiplied by the appropriate external zone coeff. GCpf, so for example 2OH denotes:
2OH = qh * GCpf2
Which is the same as zone 2 except there is no internal pressure coeff. applied.
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
If there are no overhangs set the overhang values to zero, I will need to add in a footnote about that later just to clarify.
Not a finished product yet, not by a long shot. The current todo list includes the following:
To Do List:
1) Calculate min. lateral load with roof forces neglected and min. pressures of 8 psf and 16 psf on roof and walls respectively. (psf)
2) Calculate max. uplift and max. horizontal reactions of trusses or rafters assuming 24" o/c and 16" o/c for design of hurricane ties (lbs).
3) Calculate base wind shear in transverse and longitudinal direction (lbs).
4) Calculate shear wall reactions (lbs) and unit shear (plf) assuming only external shear walls (4 walls).
5) Calculate roof diaphragm distributed load (plf) assuming one story building with external shear walls only.
6) Include C & C wind loads for component design.
7) Include Directional Procedure as a comparison to Envelope Procedure or setup separate calculator for this method.
8) Complete PDF report output.
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable
RE: Wind Envelope Procedure with a Half Hip Roof and Dutch Gable