Uncommon Type WWF As Calculation
Uncommon Type WWF As Calculation
(OP)
Hi all,
I am trying to check a roof slab capacity of an existing building designed in 1971. The slab reinforcement was called out "4x10-#1/#8 x 5' WIDE WWF" and "4 Pieces of 4x6 - #2/ 1/4" WWF". With little experience with WWF, I looked up the ACI318 as well as concrete book but hardly find any WWF combination similar to the callouts. Can anyone with experience help me out?
For the callout "4x10-#1/#8 x 5' WIDE WWF", I'm not sure what is #1/#8. I also don't know why it says "x 5'"
For the callout "4 Pieces of 4x6 - #2/ 1/4" WWF", I'm not sure why it calls out "4 Pieces"
My goal is to calculate the area of steel "As" for these two callouts. Please help.
Thanks!!!
I am trying to check a roof slab capacity of an existing building designed in 1971. The slab reinforcement was called out "4x10-#1/#8 x 5' WIDE WWF" and "4 Pieces of 4x6 - #2/ 1/4" WWF". With little experience with WWF, I looked up the ACI318 as well as concrete book but hardly find any WWF combination similar to the callouts. Can anyone with experience help me out?
For the callout "4x10-#1/#8 x 5' WIDE WWF", I'm not sure what is #1/#8. I also don't know why it says "x 5'"
For the callout "4 Pieces of 4x6 - #2/ 1/4" WWF", I'm not sure why it calls out "4 Pieces"
My goal is to calculate the area of steel "As" for these two callouts. Please help.
Thanks!!!






RE: Uncommon Type WWF As Calculation
Again that may be slightly incorrect but I believe that's how it was explained to me once.
RE: Uncommon Type WWF As Calculation
WWF (or WWR as it's now called) is not much different from rebar calculation wise. Instead of the bars being placed and tied they are placed in welded sheets. They may or may not be deformed which might change development length.
For the 4x10-#1/#8 5' wide WWF you have the equivalent of #1 bars (1/8" diameter) at 4" o.c. with #8 bars at 10" o.c. the other way. The sheet is 5' wide.
For the 4x6-#2/1/4" WWF you have the equivalent of #2 bars (2/8" diameter) at 4" o.c. with 1/4" (2/8" diameter again) bars at 6" o.c. the other way.
From these you can calculate an equivalent reinforcement area by summing the cross sectional area of each "bar" in a unit length.
Maine EIT, Civil/Structural.
RE: Uncommon Type WWF As Calculation
RE: Uncommon Type WWF As Calculation
LonnieP
RE: Uncommon Type WWF As Calculation
#1 = 0.2893" = 7.348 mm diameter
#8 = 0.1285" = 3.264 mm diameter
#9 = 0.1144" = 2.906 mm diameter
I searched for "#9 wire diameter" and Wikipedia was the first link listed.
www.PeirceEngineering.com
RE: Uncommon Type WWF As Calculation
RE: Uncommon Type WWF As Calculation
Maine EIT, Civil/Structural.