Clarification required for ASME SEC VIII DIV 2 - reg.,
Clarification required for ASME SEC VIII DIV 2 - reg.,
(OP)
Hi,
In ASME SEC VIII DIV 2, Design Rules for Supports and Attachments, There are two formulas for calculating angle ρ,
ie) ρ = tan ρ[0.5+(∏-ß)cotß].
ρ = -158.58+7.8668θ-8.8037(10)-2θ2+4.3011(10)-4θ3-8.0644(10)-7θ4
Can anyone pls. suggest me which one can I use to calculate ρ for Stress coefficients (K9,K10) for horizontal vessels on saddle supports?
Thanks,
VIJAYAN S A
In ASME SEC VIII DIV 2, Design Rules for Supports and Attachments, There are two formulas for calculating angle ρ,
ie) ρ = tan ρ[0.5+(∏-ß)cotß].
ρ = -158.58+7.8668θ-8.8037(10)-2θ2+4.3011(10)-4θ3-8.0644(10)-7θ4
Can anyone pls. suggest me which one can I use to calculate ρ for Stress coefficients (K9,K10) for horizontal vessels on saddle supports?
Thanks,
VIJAYAN S A





RE: Clarification required for ASME SEC VIII DIV 2 - reg.,
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RE: Clarification required for ASME SEC VIII DIV 2 - reg.,
In above formulae, the first one needs the value of ρ(highlighted in red color),
ie) ρ = tan ρ[0.5+(∏-ß)cotß].
I am confused with the similar notation like ρ, where can I get the value of ρ(highlighted in red color).
If you say, use the second formulae, then it wont matching with the table value given in code itself. Please, see my below calculation.
Let θ=120 degree
= 2.09439 radian
ß=∏-(θ/2)
=∏-(2.09439/2)
=2.094395 radian
By using second formula (interpolating function),
ρ = -142.48 radian
When I substitute the above ρ value in first forumula (theoretical one),
I will get, ρ=-0.5902 rad
=-33.82 degree
But the table value is for θ=120 degree; ρ = 93.667 degree.
Please, Clarify....
RE: Clarification required for ASME SEC VIII DIV 2 - reg.,
VIJAYAN S A
RE: Clarification required for ASME SEC VIII DIV 2 - reg.,
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RE: Clarification required for ASME SEC VIII DIV 2 - reg.,