ASCE 7 Ice Load Provisions for Netting
ASCE 7 Ice Load Provisions for Netting
(OP)
I need to figure out the ice load on some netting but am getting a nnumber that can't be correct. The equations are straight forward. ASCE 7-10 by the way.
t = 0.5"
Vc = 30 mph
temperature = 15 degrees Farenheit
Kzt = 1.0
Ii = 1.0
Dc = .0945 in.
Per 10.4-4
fz= 0.980
Per 10.4-5
td = .98 inches
This seems pretty consrevative to me since we only get a few freezing days per year.
Per 10.4-1
Ai = 3.3 in2
This seems way to high. After mutliplying 0.7 to get to ASD in corresponds to roughly .86 inch thickness of ice.
Anybody see something wrong with my calcs?
t = 0.5"
Vc = 30 mph
temperature = 15 degrees Farenheit
Kzt = 1.0
Ii = 1.0
Dc = .0945 in.
Per 10.4-4
fz= 0.980
Per 10.4-5
td = .98 inches
This seems pretty consrevative to me since we only get a few freezing days per year.
Per 10.4-1
Ai = 3.3 in2
This seems way to high. After mutliplying 0.7 to get to ASD in corresponds to roughly .86 inch thickness of ice.
Anybody see something wrong with my calcs?
KGH






RE: ASCE 7 Ice Load Provisions for Netting
Remember that the code is not designing for your few freezing days, but a condition more drastic, based on local conditions. In the Pacific Northwest, I have seen ice storms on two occasions over the past 60 years where at least 1/2" of radial ice was deposited, and we rarely get long freezing stretches either, or ice storms for that matter. Those storms were within the last 20 years and are a real rarity, but they do happen.
7/8" of radial ice does not seem unreasonable to me.
Mike McCann
MMC Engineering
RE: ASCE 7 Ice Load Provisions for Netting
RE: ASCE 7 Ice Load Provisions for Netting
RE: ASCE 7 Ice Load Provisions for Netting
KGH
RE: ASCE 7 Ice Load Provisions for Netting