Differential head calculation
Differential head calculation
(OP)
Dear Seniors,
I am using HFO as media. While calculating the pump head, i calculated pressure drop in MWC and the same i converted in MLC by using the following formulae
MLC = MWC x Specific gravity of fluid.
I have used the above formulae for all my calculations. But one of my consultant commented as MLC = MWC/ specific gravity of fluid.
Now you are reqeusted to please suggest me which one is correct.
Thanks in advance
Srinivas
I am using HFO as media. While calculating the pump head, i calculated pressure drop in MWC and the same i converted in MLC by using the following formulae
MLC = MWC x Specific gravity of fluid.
I have used the above formulae for all my calculations. But one of my consultant commented as MLC = MWC/ specific gravity of fluid.
Now you are reqeusted to please suggest me which one is correct.
Thanks in advance
Srinivas





RE: Differential head calculation
Hope, you can do rest of the calculation.
PS: Check all your calculations.
RE: Differential head calculation
however calculating pressure drop using water is also not the best as the viscosity of the fluid has a distinct impact on pressure drop.
It seems you're trying to do this very simply and not understanding the basic physics behind this.
Check lots of times before you buy the pump!
My motto: Learn something new every day
Also: There's usually a good reason why everyone does it that way
RE: Differential head calculation
Thanks for your explanation. The following is understood from your formulae
As G is gets cancel (HL = HW x Rho water/ Rho liquid). This means always Meter Liquid column height is more than Meter water column if specific gravity of fluid less than 1.
The above complies the statement of Mr. Little inch.
Thanks a lot
Regards
Srinivas
RE: Differential head calculation
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(2B)+(2B)' ?