Shear tearout from a hole to close to the edge
Shear tearout from a hole to close to the edge
(OP)
I am currently trying to figure out the tear out strength of an A36 steel pad-eye. The hole in the pad-eye that it will be lifted from is 2" in diameter and 2.5 inches from center to the nearest edge. The problem is that the pin that will be lifting it is 1.38" in diameter and i was unsure how this effected the tear out strength? I referenced the ASME BTH-1-2011 Design of Below the Hook Lifting Devices but it wasn't helpful. I was hoping someone could give some insight on the subject. I am assuming I cant use the standard tear-out calculation which is F = Shear strength*distance from fixing center to edge*thickness I believe.





RE: Shear tearout from a hole to close to the edge
"which is F = Shear strength*distance from fixing center to edge*thickness" ... if "distance from fixing center to edge" means the minimum distance from the edge of the hole to the edge of the part*2. this is, in my experience, conservative.
the other thing to check is bearing, with e/D < 1.5.
Quando Omni Flunkus Moritati
RE: Shear tearout from a hole to close to the edge
RE: Shear tearout from a hole to close to the edge
RE: Shear tearout from a hole to close to the edge
Quando Omni Flunkus Moritati
RE: Shear tearout from a hole to close to the edge
RE: Shear tearout from a hole to close to the edge
Contact stress between two cylinders , fig 9-9
Max Compressive Stress= Po
P1 load per axial inch on cylinder, R1 radius pin, E1 Modulus pin, R2 radius plate hole, E2 modulus plate
Po=0.591*sqrt((P1*E1*E2)*(E1+E2)*(1/R1-1/R2))
Contact zone
a=1/2 width of contact area, P1=load/axial inch
a=1.076*sqrt((P1*R1*R2/(R2-R1)*(1/E1-1/E2))
also see
ASME BTH-1–2008
3-3.3.1 Static Strength of the Plates.
RE: Shear tearout from a hole to close to the edge
Take a look at thread507-360145: DNV Pad Eye check., in the Struct. Forum. It is on the same topic and has some more info. and discussion.